As the amplitude of a sound wave increases the pitch of the ringing would be much higher (like if you were to inhale helium.. just with a phone)
Answer:
Your question was incomplete so here is the complete question and answer.
Q. When exercising in the heat, which of the following hydration strategies is best for temperature regulation during an event (e.g., 10K race)
a) plain water
b) 5-7 percent glucose solution
c) Glucose polymer solution of 6-8 percent
d) There appears to be no difference among these different forms of hydration techniques relative to temperature regulation.
Ans. d) There appears to be no difference among these different forms of hydration techniques relative to temperature regulation.
Explanation:
Temperature Regulation is an important phenomenon for the person exposed to extreme hot conditions or weather. Exercising in hot conditions increase the body temperature. Greater and intense exercise, greater the production of heat. Then the heat dissipation takes place in the form of excessive sweating which results in dehydration. That was just the brief overview of temperature regulation. Above mentioned techniques are equally good hydration techniques so there is no difference at all. You can have a plain water or glucose solutions of above mentioned percentages.
Answer:
Civilization's planet is most likely to be doomed because within the next million years the red giant star will possibly supernova.
Explanation:
Civilization's planet is most likely to be doomed because within the next million years the red giant star will possibly supernova. The supernova is the bursting of the star that has reached its end life. This leads to release of massive amount of energy, which can be more than the heat and energy released by the sun.
Answer:
103063860 Pa
Explanation:
= Density of seawater = 1030 kg/m³
g = Acceleration due to gravity = 9.81 m/s²
h = Depth at which pressure is being measured = 10.2 km
The gauge pressure is given by
Therefore, the gauge pressure at a depth of 10.2 km is 103063860 Pa
Answer:
The angular speed of the Crab nebula pulsar is 190.3 rad/s.
Explanation:
Given that,
Time T= 33 ms = 0.033 s
The angular speed is equal to the 2π divided by time period.
We need to calculate the angular speed of the Crab nebula pulsar
Using formula of angular speed
Where, T = time
= angular speed
Put the value into the formula
Hence, The angular speed of the Crab nebula pulsar is 190.3 rad/s.
