Heat transfer is limited to conduction and radiation only in anomalous expansion of water simply because of the temperature at which the expansion occurs and density
<h3>What is anomalous expansion of water?</h3>
Anomalous expansion of water is a property of water in which water expands instead of contracting.
- Anomalous expansion of water makes water less dense.
- The major effect of this anomalous expansion it will still remain less dense and at the surface of water.
- Interestingly, this expansion occurs when it is cooled from 4°C to 0°C.
Learn more about properties of water:
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Answer:
m1/m2 = 0.51
Explanation:
First to all, let's gather the data. We know that both rods, have the same length. Now, the expression to use here is the following:
V = √F/u
This is the equation that describes the relation between speed of a pulse and a force exerted on it.
the value of "u" is:
u = m/L
Where m is the mass of the rod, and L the length.
Now, for the rod 1:
V1 = √F/u1 (1)
rod 2:
V2 = √F/u2 (2)
Now, let's express V1 in function of V2, because we know that V1 is 1.4 times the speed of rod 2, so, V1 = 1.4V2. Replacing in the equation (1) we have:
1.4V2 = √F/u1 (3)
Replacing (2) in (3):
1.4(√F/u2) = √F/u1 (4)
Now, let's solve the equation 4:
[1.4(√F/u2)]² = F/u1
1.96(F/u2) =F/u1
1.96F = F*u2/u1
1.96 = u2/u1 (5)
Now, replacing the expression of u into (5) we have the following:
1.96 = m2/L / m1/L
1.96 = m2/m1 (6)
But we need m1/m2 so:
1.96m1 = m2
m1/m2 = 1/1.96
m1/m2 = 0.51
if in series one lightbulb burns out the rest are unable to turn on.
In parallel a single light bulb burns out any other light bulbs are able to work.
Parallel is the best to use during holidays.
Answer:
The mass of the banana is m and it is at height h.
Applying the Law of Conservation of Energy
Total Energy before fall = Total Energy after fall
= 
Here, total energy is the sum of kinetic energy and potential energy
+ 
= 
+ 
(a)
When banana is at height h, it has
= 0 and = mgh
and when it reaches the river, it has
= 1/2m
and = 0
Putting the values in equation (a)
0 + mgh = 1/2m + 0
mgh = 1/2m
<em>cutting 'm' from both sides</em>
<em> </em>gh = 1/2
v = 
Hence, the velocity of banana before hitting the water is
v =
You multiply the mass by the acceleration 82*7.5=615; that's what I would do
