The answer is 200 J
The kinetic energy (KE) is:
KE = 1/2 m * v²
m - mass of the object
v - velocity of the object
We have:
m = 4 kg
v = 10 m/s
KE = 1/2 * 4 kg * 10² m/s
KE = 200 J
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Are the answers.
Hope this helps. :)
The amount of sample that is left after a certain period of time, given the half-life, h, can be calculated through the equation.
A(t) = A(o) (1/2)^(t/d)
where t is the certain period of time. Substituting the known values,
A(t) = (20 mg)(1/2)^(85.80/14.30)
Solving,
A(t) = 0.3125 mg
Hence, the answer is 0.3125 mg.
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