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3 years ago

Solve w = t(r1 + r2) for t.

Mathematics

2 answers:

MatroZZZ [7]3 years ago

6 0

Answer:

The solution for t is $\frac{w}{(r_1+r_2)}$

Step-by-step explanation:

The given expression is $w = t(r_1+r_2)$

We need to solve for the 't' ,

To solve for t, divide $w = t(r_1+r_2)$ by $(r_1+r_2)$

$\frac{w}{(r_1+r_2)} = t$

Hence, The solution for t is $\frac{w}{(r_1+r_2)}$

kiruha [24]3 years ago

5 0

I think it would be:

w / (r1 + r2) = t

But I'm not sure

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16 increased by twice a number is -24 what is the solution?

Lynna [10]

Let x = the number.

"increased by" tells you we are adding.

"twice a number" tells you 2 times a number.

16 + 2x = - 24

Subtract 16 from both sides so that we have the variable on one sides and the constants on the other.

2x = - 24 - 16

2x = - 40

Divide by 2 to isolate the variable.

x = - 40/2 = - 20

Your solution is - 20.

To check your answer, plug in.

16 + 2(-20) = - 24

16 - 40 = - 24

- 24 = - 24

3 0

3 years ago

Write 28 + 24 as a product of two factors using the GCF and the distributive property

Harman [31]

Answer:

4 x 13

Step-by-step explanation:

GCD of 28 and 24 is 4

28 = 4 x 7

24 = 4 x 6

u take the 4 out

4 (7 + 6)

4 x 13

6 0

2 years ago

Read 2 more answers

Tennis elbow is thought to be aggravated by the impact experienced when hitting the ball. The article "Forces on the Hand in the

Gnoma [55]

Answer:

Step-by-step explanation:

Hello!

The objective is to study whether there is a greater force after impacting on one- handed backhand drive in advanced tennis players than in intermediate tennis players.

Sample 1: Advanced tennis players

X₁: Force (N) on the hand just after impact on a one- handed backhand drive for an advanced tennis player.

n₁= 6

X[bar]₁= 40.29 N

S₁= 11.29

Sample 2: Intermediate players

X₂: Force (N) on the hand just after impact on a one- handed backhand drive for an intermediate tennis player.

n₂= 8

X[bar]₂= 21.40

S₂= 8.30

Assuming that both variables have a normal distribution and both population variances are equal, to compare these two populations is best to do so trough their population means using a t-test for independent samples.

If the force is greater for the advanced players than for the intermediate players, then you'd expect the population mean for the advanced players to be greater than the population mean for the intermediate players:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

α: 0.05

$t= \frac{(X_[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}$

$Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{5*127.51+7*68.92}{6+8-2} }= 9.66$

$t_{H_0}= \frac{(40.29-21.40)-0}{9.66\sqrt{\frac{1}{6} +\frac{1}{8} } } = 3.62$

Using the p-value approach, the decision rule is

If p-value ≤ α, reject the null hypothesis

If p-value > α, do not reject the null hypothesis

The p-value for this test is 0.00024, it is less than the level of significance, so the decision is to reject the null hypothesis.

This means that at a 5% significance level you can conclude that the average force experienced on the hand after a one-handed backhand drive for advanced players is greater than the average force experienced on the hand after a one-handed backhand drive for intermediate players.

I hope this helps!

3 0

3 years ago

A fruit vendor has 28 pears and 16 oranges.

Westkost [7]

<span>16:28 is the ratio But you have to get that in the simplest form so it would be 4:7</span>

3 0

3 years ago

Read 2 more answers

You have 6L of water that has 20 percent strawberry juice. How many litres of an 80 percent strawberry juice should be added to

Kaylis [27]

Answer:

you are right

Step-by-step explanation:

7 0

2 years ago