Question

A worker uses a cart to move a load of bricks a distance of 10m across a parking lot. if he pushes the cart with a constant force of 209 N, what amount of work does he do?

Answer 1

Answer:

2090 J

Explanation:

the work done to move the cart is equal to the product between the force applied and the distance traveled:

$W=Fd$

In this case, the force applied is F=209 N, while the distance covered is d=10 m, therefore the work done is

$W=Fd=(209 N)(10 m)=2090 J$

Answer 2

Work is done when a body undergoes a displacement. It is the product of the force acted on the object and the distance traveled. It has SI units of Nm. It is expressed as:
Work = F x d
Work = 209 N x 10 m
Work = 2090 Nm