Would you expect the two species to compete for food on this island? Support your answer with an explanation.
2 answers:
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Without air resistance, the ball would reach a height of h = 31.9 m(pic 1)
The gravitational potential energy difference would be ΔU = 62.588J - 43.164J = 19,424J (pic2 + 3)
The work done by air resistance must be equal to the energy difference(pic4)
The magnitude of the air resistance: F = 0.883N
The gravitational potential energy difference would be ΔU = 62.588J - 43.164J = 19,424J (pic2 + 3)
The work done by air resistance must be equal to the energy difference(pic4)
The magnitude of the air resistance: F = 0.883N
Answer:
The angle of elevation of the Sun = 41.8°
Explanation:
Let the angle of elevation of the sun be θ
Using trigonometric relations,
Tan θ = opp/adj
opp = the height of the Washington Tower = 555 ft
adj = the length of the shadow = 620 ft
Tan θ = (555/620) = 0.8952
θ = Tan⁻¹ (0.8952) = 41.8°
Hence, the angle of elevation of the Sun = 41.8°
Answer:
a) 15.77 m/sec2
b) 13.3 deg
Explanation:
we are given;
Flea force = F1=1.07×10⁻5 N j
Breeze force = F2 = 1.14× 10⁻6 N (-j
mass of flea =6.0 ×10⁻7 kg
So net force on the flea=F1+F2+weight of flea=1.07×10⁻5 j +1.14× 10⁻6 i + 6.0 ×10⁻7 (-j) ×9.8= ma
==> ma = 1.07×10⁻5 j - 0.588×10⁻5 j + 0.114×10⁻5 i
==> ma= 0.482 ×10⁻5 j +0.114×10⁻5 i
==> ma = 0.114×10⁻5 i +0.482 ×10⁻5 j
== a = (0.114×10⁻5 i +0.482 ×10⁻5 j) / 6.0 ×10⁻7
==> a =
==>a= (1.9 j+8.03 i ) m/sec2
mag of a = 15.77 m/sec2
direction angle = tan⁻1(1.9/8.03)=13.3°