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The given elements put into an equation using their symbols are as follows:
Pb +
![AgC_{2}H_{3}O_{2}](https://tex.z-dn.net/?f=AgC_%7B2%7DH_%7B3%7DO_%7B2%7D%20)
=
![Pb(II){(C_{2}H_{3}O_{2})_2}](https://tex.z-dn.net/?f=Pb%28II%29%7B%28C_%7B2%7DH_%7B3%7DO_%7B2%7D%29_2%7D)
+ Ag
Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb +
![AgC_{2}H_{3}O_{2}](https://tex.z-dn.net/?f=AgC_%7B2%7DH_%7B3%7DO_%7B2%7D%20)
=
![Pb(II){(C_{2}H_{3}O_{2})_2}](https://tex.z-dn.net/?f=Pb%28II%29%7B%28C_%7B2%7DH_%7B3%7DO_%7B2%7D%29_2%7D)
+ Ag
Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb +
![2AgC_{2}H_{3}O_{2}](https://tex.z-dn.net/?f=2AgC_%7B2%7DH_%7B3%7DO_%7B2%7D%20)
=
![Pb(II){(C_{2}H_{3}O_{2})_2}](https://tex.z-dn.net/?f=Pb%28II%29%7B%28C_%7B2%7DH_%7B3%7DO_%7B2%7D%29_2%7D)
+ Ag
Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb +
![2AgC_{2}H_{3}O_{2}](https://tex.z-dn.net/?f=2AgC_%7B2%7DH_%7B3%7DO_%7B2%7D%20)
=
![Pb(II){(C_{2}H_{3}O_{2})_2}](https://tex.z-dn.net/?f=Pb%28II%29%7B%28C_%7B2%7DH_%7B3%7DO_%7B2%7D%29_2%7D)
+ 2Ag
That is your final equation
The coefficients are 2 + 2 = 1 + 2
Force /Area = Pressure
Force = Pressure * Area
<span>Force = 1065 * 17 = 18105 N</span>
I’m thinking it’s gold because lead isn’t with cooper meaning that if u switch lead with cooper it won’t work at all .
It changes from a liquid from to a solid.
I hope this helps!