Answer:
the systematic name is called Lithium sulfide.
Answer:
0.098 moles
Explanation:
Let y represent the number of moles present
1 mole of Ba(OH)₂ contains 2 moles of OH- ions.
Hence, 0.049 moles of Ba(OH)2 contains y moles of OH- ions.
To get the y moles, we then do cross multiplication
1 mole * y mole = 2 moles * 0.049 mole
y mole = 2 * 0.049 / 1
y mole = 0.098 moles of OH- ions.
1 mole of OH- can neutralize 1 mole of H+
Therefore, 0.098 moles of HNO₃ are present.
2 ICl + H2 ----> I2 + 2 HCl
as given that rate is first order with respect to ICl and second order with respect to H2
The rate law will be
Rate = K [ICl] [ H2]^2
b) Given that K = 2.01 M^-2 s^-1
Concentrations are
[ICl] = 0.273 m and [H2] = 0.217 m
Therefore rate = 2.01 X (0.273)(0.217)^2 = 0.0258 M / s
Answer:
The sample of lead has a volume of 11.1 cm³
Explanation:
<u>Step 1:</u> Data given
x cm³ lead has a density of 11.3 g/cm³
it has the same mass as 330cm³ of a piece of redwood with density 0.38g/cm³
<u>Step 2</u>: Calculate mass of the piece of redwood
Density = mass/volume
mass = density * volume
Mass of the piece of redwood = 0.38 g/cm³ * 330cm³ = 125.4 grams
Since the sample of lead has the same mass, it also has a mass of 125.4 grams
<u>Step 3</u>: Calculate volume of the lead
Density = mass/ volume
Volume = mass/ density
Volume of lead = 125.4g / 11.3g/cm³ = 11.097 cm³≈11.1 cm³
The sample of lead has a volume of 11.1 cm³
