What volume would 8.01×1022 molecules of an ideal gas occupy at STP?
1 answer:
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Explanation:
The given data is as follows.
T = 298 K, = -5645 kJ/mol
= -5798 kJ/mol
Relation between and
are as follows.
=
-5798 kJ/mol = -5645 kJ/mol -
-153 kJ/mol = -
= 0.513 kJ/mol K
Now, temperature is = (37 + 273) K = 310 K
Since, =
=
= (-5645 kJ/mol - 159.03 kJ/mol)
= -5804.03 kJ/mol
As, change in Gibb's free energy = maximum non-expansion work
= -5804.03 kJ/mol - (-5798 kJ/mol)
= -6.03 kJ/mol
Therefore, we can conclude that the additional non-expansion work is -6.03 kJ/mol.