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kolezko [41]
3 years ago
9

Which of these reactions can be classified as double replacement reactions?

Chemistry
1 answer:
Kryger [21]3 years ago
4 0
1) Zn + 2 HCl = ZnCl2 + H2 ( <span>single replacement )

2) </span>2 NaCl + F2 = 2 NaF + Cl2 ( <span>single replacement )

3) </span>2 AlBr3 + 3 K2SO4 = 6 KBr + Al2(SO4)3 ( <span>double replacement )

4) </span>2 K + MgBr2 = 2 KBr + Mg ( <span>single replacement )

Answer 3

hope this helps!</span>
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Please help me with chemistry
vodka [1.7K]

Table Giving Answer

Element Atomic mass % Amount

Mg_24     24                79    18.96

Mg_25 25                10    2.5

Mg_26 26                11   2.86

   

Total                     24.32

Discussion

The method of calculation for this table, which was done in Excel (a spread sheet) is shown below. Assume that there is 100 grams of material of "pure" magnesium. What is it's mass?

<em><u>Sample  Calculation</u></em>

The the sample atomic mass = 24

Mass = % * sample atomic mass

Mass = 79% * 24

Mass = (79/100) * 24

Mass = 18.96

<em><u>Note</u></em>

The other two elements are found exactly the same as the sample calculation.

Then all you do is add the 3 masses together.

Answer

The mass of Mg to 1 decimal place is 24.3 <<<< Answer.


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4vir4ik [10]
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I hope that helps!
8 0
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Which formula represents an ionic compound?
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Diano4ka-milaya [45]

I don't know if this is multiple choice but if it isn't I can name of few.

Fun Fact: Noble Metals are chemical elements that have outstanding tolerance and resistance to oxidation.

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Other: Ruthenium, osmium, and rhodium.

<em>Hope this helps!</em>

6 0
3 years ago
How does changing the volume or temperature of a gas affect the pressure of that gas?
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Answer:

When a gas occupies a smaller volume, it exerts a higher pressure; when it occupies a larger volume, it exerts a lower pressure (assuming the amount of gas and the temperature do not change). Since P and V are inversely proportional, a graph of 1/P vs. V is linear.

Explanation:

<h2><u><em>This is all I know.</em></u></h2><h2><u><em>Hope it helps~</em></u></h2><h2><u><em>Good luck with your work!!~</em></u></h2>
6 0
2 years ago
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