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3 years ago

5

A tire at 21ÁC has a pressure of 0.82 atm. Its temperature decreases to _3.5ÁC. If there is no volume change in the tire, what i

s the pressure after the temperature change?

1 answer:

amid [387]3 years ago

3 0

Volumen = constant => P/T = constant

T1 = 21°C + 273.15 = 294.15 k
P1 = 0.82 atm

T2 = - 3.5°C + 273.15 = 269.65 k
P2 = ?

P2 / 269.65k = 0.82atm / 294.15k

P2 = [0.82atm / 294.15k] * 269.65kg = 0.75 atm

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When $K_{p}>Q_p$ ; the reaction is product favored.
When $K_{p}$ ; the reaction is reactant favored.
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