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Reptile [31]
3 years ago
5

A tire at 21ÁC has a pressure of 0.82 atm. Its temperature decreases to _3.5ÁC. If there is no volume change in the tire, what i

s the pressure after the temperature change?
Chemistry
1 answer:
amid [387]3 years ago
3 0
Volumen = constant => P/T = constant

T1 = 21°C + 273.15 = 294.15 k
P1 = 0.82 atm

T2 = - 3.5°C + 273.15 = 269.65 k
P2 = ?

P2 / 269.65k = 0.82atm / 294.15k

P2 = [0.82atm / 294.15k] * 269.65kg = 0.75 atm
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Answer:

–2733.4 KJ

Explanation:

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From the balanced equation above,

1 mole of C₂H₅OH reacted to produce enthalpy change (ΔH) of −1366.7 kJ.

Finally, we shall determine the enthalpy change (ΔH) produced by the reaction of 2 moles of C₂H₅OH. This can be obtained as follow:

From the balanced equation above,

1 mole of C₂H₅OH reacted to produce enthalpy change (ΔH) of −1366.7 kJ.

Therefore, 2 moles of C₂H₅OH will react to produce enthalpy change (ΔH) of = 2 × −1366.7 = –2733.4 KJ.

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