Which of the following is the correct SI unit measuring amount of material contained in a solid sphere

What are the correct methods of heat transfer

Crank

<h2>Conduction, Convection, and Radiation</h2>

Explanation:

The transfer of heat generally depends on the difference in the temperature in the surroundings.

The best methods for the transfer of heat are conduction convection, radiation and sometimes evaporation also.

Conduction: This is the transfer of heat through the system that is solid.
Convection: Convection is the process in which warm surfaces of a liquid or gas rises to cooler surfaces in the liquid or gas that is the transfer of heat from the surface. Natural convection occurs as air is heated: it expands, rises, and is replaced by cooler air.
Radiation: This is a process where energy is radiated among the surroundings in the form of electromagnetic radiation.
Evaporation: The latent heat of a liquid is used to transfer heat by absorbing the energy needed to evaporate that liquid. The heat absorbed is released by condensing the liquid outside the enclosure.

6 0

4 years ago

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A 45.0-kg person steps on a scale in an elevator. The scale reads 460 n. What is the magnitude of the acceleration of the elevat

WINSTONCH [101]

Answer:

The magnitude of the acceleration of the elevator is 0.422 m/s²

Explanation:

Lets explain how to solve the problem

Due to Newton's Law ∑ Forces in direction of motion is equal to mass

multiplied by the acceleration

We have here two forces 460 N in direction of motion and the weight

of the person in opposite direction of motion

The weight of the person is his mass multiplied by the acceleration of

gravity

→ W = mg , where m is the mass and g is the acceleration of gravity

→ m = 45 kg and g = 9.8 m/s²

Substitute these values in the rule above

→ W = 45 × 9.8 = 441 N

The scale reads 460 N

→ F = 460 N , W = 441 N , m = 45 kg

→ F - W = ma

→ 460 - 441 = 45 a

→ 19 = 45 a

Divide both sides by 45

→ a = 0.422 m/s²

<em>The magnitude of the acceleration of the elevator is 0.422 m/s²</em>

4 0

4 years ago

In a machining operation that approximates orthogonal cutting, the cutting tool has a rake angle =100 . The chip thickness ratio

Rudik [331]

Answer:

The percentage of the total energy dissipated into shear plane is 89.46%.

Explanation:

Given that,

Rake angle = 10°

Thickness ratio= 0.5

Cutting Force = 400 N

Thrust force = 200 N

Speed =3 m/s

Suppose the shear force is 345.21 N.

We need to calculate the shear plane angle

Using formula shear angle

$\tan\phi=\dfrac{r\cos\alpha}{1-r\sin\alpha}$

Put the value in to the formula

$\tan\phi=\dfrac{0.5\cos10}{1-0.5\sin10}$

$\tan\phi=0.539$

$\phi=\tan^{-1}(0.539)$

$\phi=28.32^{\circ}$

We need to calculate the shear velocity

Using formula of shear velocity

$v_{2}=\dfrac{v\cos\alpha}{\cos(\phi-\alpha)}$

Put the value into the formula

$v_{2}=\dfrac{3\times\cos10}{\cos(28.32-10)}$

$v_{2}=3.11\ m/s$

We need to calculate the percentage of the total energy dissipated into shear plane

Using formula of energy dissipated

$\%d=\dfrac{P_{s}}{P}\times100$

$\%d=\dfrac{F_{s}\times v_{c}}{F_{c}\times v}\times100$

Put the value into the formula

$\%d=\dfrac{345.21\times3.11}{400\times3}\times100$

$d=89.46\%$

Hence, The percentage of the total energy dissipated into shear plane is 89.46%.

6 0

3 years ago

__________ is the term for a reaction where energy is released.

Ivenika [448]

Exothermic is the term for a reaction where energy is released.

4 0

3 years ago

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A straight wire is aligned east-west in a region where Earth’s magnetic field has magnitude 0.0780 mT and direction 67.1° below

Sergio [31]

Explanation:

It is given that,

Earth's magnetic field, $B=0.078\ mT=0.078\times 10^{-3}\ T$

Direction of magnetic field, 67.1 degrees below the horizontal, with the horizontal component directed due north.

The magnetic force on the wire per unit length of wire, $\dfrac{F}{L}=0.0300\ N/m$

(a) The given scenario is shown in the attached figure as :

Using the right hand rule to find the direction of magnetic force on the wire. By using this rule, we get the magnetic force acting on the wire is in upward direction.

(b) Let I is the current flowing in the wire. The magnetic force is given by the following formula as:

$F=ILB$

$I=\dfrac{F}{LB}$

$I=\dfrac{0.0300}{0.078\times 10^{-3}}$

I = 384.61 A

Hence, this is the required solution.

7 0

3 years ago