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Serga [27]
3 years ago
10

Standing still, Bruce, the quarterback, gets tackled by Biff, the 90.0-kg tackle, who is traveling at 7.0 m/s. Upon collision, B

iff stops and Bruce goes flying off at 10 m/s. What is Bruce's Mass?​
Physics
2 answers:
Orlov [11]3 years ago
5 0

Answer:

Bruces mass is 63kg

Explanation:

⟼ΔP=P

⟼m1v1=m2v2

⟼90(7)=m2(10)

⟼10m2=630

⟼m2= 630/10

⟼m2=63kg

tatyana61 [14]3 years ago
3 0

\\ \sf\longmapsto \Delta P=P

\\ \sf\longmapsto m1v1=m2v2

\\ \sf\longmapsto 90(7)=m2(10)

\\ \sf\longmapsto 10m2=630

\\ \sf\longmapsto m2=\dfrac{630}{10}

\\ \sf\longmapsto m2=63kg

Bruces mass is 63kg

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The total energy in a substance as a result of the motion and position of all the particles is _________. a. heat b. temperature
bonufazy [111]
The answer would be Thermal Energy.
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3 years ago
Wegener believed continents moved, but he did not know how. Identify what needed to happen before Wegener's idea about moving co
pochemuha

D. Advances in technology were needed to gather more evidence.

Explanation:

New technologies had to be developed to ascertain Wegener's claims.

The major flaw in Wegener's postulate was that the moving continents lacked a mechanism to drive them into motion.

His theory needed more scientific backing also.

  • A major leap was made when new technologies used during the second world war was deployed to investigate the ocean floor.
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Learn more:

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6 0
3 years ago
A car traveling with constant speed travels 150 km in 7200s what is the speed of the car
Oksana_A [137]
Velocity is distance/time 

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5 0
3 years ago
How much heat is needed to melt 13.74 kg of silver that is initially at 20°C?
salantis [7]

Answer:

Q = 4.63 \times 10^6 J

Explanation:

As we know that melting point of silver is

T = 961.8 degree C

Latent heat of fusion of silver is given as

L = 111 kJ/kg

specific heat capacity of silver is given as

s = 240 J/kg C

now we will have

Q = ms\Delta T + mL

\Delta T = 961.8 - 20

\Delta T = 941.8 degree C

now from above equation

Q = (13.74)(240)(941.8) + (13.74)(111 \times 10^3)

Q = 3.1 \times 10^6 + 1.53 \times 10^6

Q = 4.63 \times 10^6 J

3 0
3 years ago
During an experiment of momentum, trolley, X, of mass (2.34 ± 0.01) kg is moving away from another trolley, Y, of mass (2.561 ±
Alla [95]

Answer:

P = 1 (14,045 ± 0.03 )  k gm/s

Explanation:

In this exercise we are asked about the uncertainty of the momentum of the two carriages

            Δ (Pₓ / Py) =?

 Let's start by finding the momentum of each vehicle

car X

        Pₓ = m vₓ

        Pₓ = 2.34 2.5

        Pₓ = 5.85 kg m

car Y

        Py = 2,561 3.2

        Py = 8,195 kgm

How do we calculate the absolute uncertainty at the two moments?

          ΔPₓ = m Δv + v Δm

          ΔPₓ = 2.34 0.01 + 2.561 0.01

          ΔPₓ = 0.05 kg m

         ΔP_{y} = m Δv + v Δm

         ΔP_{y} = 2,561 0.01+ 3.2 0.001

         ΔP_{y} = 0.03 kg m

now we have the uncertainty of each moment

          P = Pₓ / P_{y}

          ΔP = ΔPₓ/P_{y} + Pₓ ΔP_{y} / P_{y}²

          ΔP = 8,195 0.05 + 5.85 0.03 / 8,195²

          ΔP = 0.006 + 0.0026

          ΔP = 0.009 kg m

The result is

           P = 14,045 ± 0.039 = (14,045 ± 0.03 )  k gm/s

7 0
3 years ago
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