Answer:
of are found in 39.5 grams of .
Explanation:
Atomic weights : P= 31, F= 19,
molar mass of = 1 atomic weight of P+ 5 atomic weight of
F= 31+5 19
= 31+95
=126 g/mole
moles in 39.5 gm of
=
=
=0.3134 moles
1 mole of any substance contains
0.3131 moles contains 0.3134
Therefore, of are found in 39.5 grams of .
In the Lewis structure of PO43- there are a total of 32 valence electrons. For the Lewis structure for PO4 3- you should take formal charges into account to find the best Lewis structure for the molecule. Remember, PO4 3- has a negative three charge on the molecule.
<u>Answer:</u> The equilibrium constant for this reaction is
<u>Explanation:</u>
The equation used to calculate standard Gibbs free change is of a reaction is:
For the given chemical reaction:
The equation for the standard Gibbs free change of the above reaction is:
We are given:
Putting values in above equation, we get:
To calculate the equilibrium constant (at 58°C) for given value of Gibbs free energy, we use the relation:
where,
= Standard Gibbs free energy = -38.2 kJ/mol = -38200 J/mol (Conversion factor: 1 kJ = 1000 J )
R = Gas constant = 8.314 J/K mol
T = temperature =
= equilibrium constant at 58°C = ?
Putting values in above equation, we get:
Hence, the equilibrium constant for this reaction is
Answer:
A. To increase enthalpy
Explanation:
Because the burner is the engine of the hot air balloon it is what propels the hot air up into the envelope to make the balloon rise
Answer:
15.63.
Explanation:
So, from the question, we are given the following parameters or data or information for solving this particular Question and they are;
(1). "semi-permeable membrane from the extracellular space ([galactose] = 2 mM) to the cytosol ([galactose] = 10 mM) under biochemically standard conditions. (R = 0.08206 L atm/mol K = 8.314 J/mol K) (15 pts.) "
(2). "If ATP hydrolysis liberates 30.5 kJ/mol at standard conditions".
(3). " (507.2 g/mol) would be required to transport 260 g of galactose from the extracellular space to the cytosol"
Step one: determine the difference to transport of galactose from extracellular space to cytosol.
This can be done by using the formula below:
Ratio = intracellular/ extracellular.
=> 10/2 = 5 mM.
Step two: so, from statement (2) and (3), the if 507.2 g/mol ATP = 30.5 kJ/mol, then 260 g/mol = ???
Therefore, 260 × 30.5 / 507.2 = 15.63 is the energy required.