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vivado [14]
4 years ago
9

In two or more complete sentences, compare combination reactions to decomposition reactions.

Chemistry
2 answers:
S_A_V [24]4 years ago
6 0
Combination: Joining of two different substances to form a more complex substance.

Decomposition: Breaking of a compound into two or more products.

I HOPE THIS HELPS! :3
algol134 years ago
3 0

Explanation:

When in a chemical reaction either two or more number of elements or compounds combine together to result in the formation of a single compound then they are known as combination reactions.

For example, 2Na(s) + Cl_{2}(g) \rightrarrow 2NaCl(s)

On the other hand, when in a chemical reaction a single compound is able to produce two or more number of products then its is known as a decomposition reaction.

For example, CuCl_{2} \rightarrow Cu + Cl_{2}

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A compound has the molecular formula C6H12O6. Which class of organic compounds does it belong to?
pishuonlain [190]

Answer:

Explanation:

C6H12O6 is the formula of simple sugar, glucose. The primary elements in the glucose are carbon, hydrogen and oxygen. Thus, glucose belongs to the group of carbohydrate.

Carbohydrates are group of bio molecules that comprises of  carbon , hydrogen and oxygen as its constituents elements. Thus all the substances that contain all three element primarily C, H and O are considered as carbohydrates.  

8 0
4 years ago
A standard room temperature and pressure, most of the elements on the periodic table are
Maslowich

Answer:

Solids

Explanation:

At standard room temperature and pressure, most of the elements are solids.

Just a few of the elements are liquids and gases at this temperature.

The periodic table is made up of metals, metalloids and non-metals. Most of these substances are actually solid.

Some non-metals are gaseous at standard room temperature.

8 0
3 years ago
The arsenic in a 1.223 g sample of a pesticide was converted to H3AsO4 by suitable treatment. The acid was then neutralized, and
Vladimir79 [104]

Answer:

5.471% As₂O₃ in the sample.

Explanation:

<em>...the reaction is: Ag+ + SCN- => AgSCN(s) Calculate the percent As2O3 in the sample. (F.W. As2O3 = 197.84 g/mol).</em>

<em />

First, with the amount of KSCN we can find the moles of Ag in the filtrates. As we know the amount of Ag added we can know the precipitate of Ag and the moles of AsO₄ = 1/2 moles of As₂O₃ in the sample:

<em>Moles KSCN = Moles Ag⁺ in the filtrate:</em>

0.01127L * (0.100mol / L)= 0.001127moles Ag⁺

<em>Total moles Ag⁺:</em>

0.0400L * (0.0781mol/L) = 0.0031564 moles Ag⁺

<em>Moles of Ag⁺ in the precipitate:</em>

0.0031564 - 0.001127 = 0.0020294 moles Ag⁺

<em>Moles AsO₄ = Moles As:</em>

0.0020294 moles Ag⁺ * (1mol As / 3 moles Ag⁺) = 6.765x10⁻⁴ moles AsO₄

<em>Moles As₂O₃:</em>

6.765x10⁻⁴ moles AsO₄ * (1 mol As₂O₃ / 2 mol AsO₄) =

3.382x10⁻⁴ moles As₂O₃

<em>Mass As₂O₃:</em>

3.382x10⁻⁴ moles As₂O₃ * (197.84g/mol) = 0.0669g As₂O₃

Percent is:

0.0669g As₂O₃ / 1.223g sample * 100 =

<h3>5.471% As₂O₃ in the sample</h3>

<em />

7 0
4 years ago
If Carl buys a 946 ml bottle of rubbing alcohol, how much of the aqueous solution is water?
Darina [25.2K]

The question is incomplete, here is the complete question:

A bottle of rubbing alcohol having aqueous solution of alcohol contains 70% (v/v) alcohol. If Carl buys a 946 ml bottle of rubbing alcohol, how much of the aqueous solution is water?

<u>Answer:</u> The amount of water present in the given bottle of rubbing alcohol is 283.8 mL

<u>Explanation:</u>

We are given:

Volume of bottle of rubbing alcohol = 946 mL

70% (v/v) alcohol solution

This means that 70 mL of rubbing alcohol is present in 100 mL of solution

Amount of water present in solution = [100 - 70] = 30 mL

Applying unitary method:

In 100 mL of solution, the amount of water present is 30 mL

So, in 946 mL of solution, the amount of water present will be = \frac{30}{100}\times 946=283.8mL

Hence, the amount of water present in the given bottle of rubbing alcohol is 283.8 mL

4 0
3 years ago
Solve for v in the formula d = v + at
Anna [14]

Answer: v=d−at

Explanation: I don't know if this will help

6 0
3 years ago
Read 2 more answers
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