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Serhud [2]
4 years ago
11

Which of the following could result from having few or no ?-1,6 linkages in glycogen? Select all that apply.

Chemistry
1 answer:
Katen [24]4 years ago
5 0

Answer:

The correct answer is 1 glycogen degradation would slow down.

Explanation:

Glycogen is the principle storage polysaccharide present in the liver and muscle of human body.

    Glycogen contain both alpha-1,4-glycosidic linkage and alpha -1,6-glycosidic linkage.During glycogenolysis some glucose residues are transferred from branch point of the glycogen to its end and thereafter a single glucose residue is linked to the branch point of glycogen by alpha-1,6-glycosidic linkage.

   The alpha-1,6-glycosidic linked glucose of glycogen is finally get separated from glycogen by the catalytic activity of alpha-1,6-glycosidase enzyme in the final step of glycogenolysis.

 According to the given question if there is no alpha-1,6-glycosidic linkage in the glycogen then glycogen degradation will slow down.

     

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At room temperature, the solubility of which solute in water would be most affected by a change in pressure?
Bad White [126]
<h3><u>Answer;</u></h3>

At room temperature, the solubility of which solute in water would be most affected by a change in pressure?

<h3><u>Explanation;</u></h3>
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4 0
4 years ago
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A 44.0mg sample of carbon reacts with sulfur to form 122 mg of the compound.
anygoal [31]

Answer:

Empirical formula = C₃S₂

Explanation:

Given data:

Mass of carbon = 44.0 mg (44/1000 = 0.044 g)

Mass of sulfur = 122 mg - 44.0 mg = 78 mg = 78/1000 = 0.078 g)

Empirical formula = ?

Solution:

First of all we will calculate the number of moles.

Number of moles of carbon = mass / molar mass

Number of moles of carbon = 0.044 g/ 12.01 g/mol

Number of moles of carbon = 0.0037 mol

Number of moles of sulfur:

Number of moles = mass / molar mass

Number of moles = 0.078 g/ 32,066 g/mol

Number of moles  = 0.0024 mol

Now we will compare the moles:

                C                            :                  S

             0.0037/0.0024        :             0.0024/0.0024

                  1.5                         :               1

C : S = 2(1.5 : 1)

C : S = 3 : 2

Empirical formula = C₃S₂

 

4 0
3 years ago
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Both would obtain the same proportions, so I don't see why putting a half cup of sugar would make things any different.

Hope this is the answer you are looking for.
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