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Citrus2011 [14]
3 years ago
10

Write the simple equation that describes the action of the enzyme catalase.

Chemistry
1 answer:
Nataly [62]3 years ago
5 0

Here we have to write a simple equation which describes the action of the enzyme catalase.

The equation is: The concentration of the complex [ES] = \frac{[E]0}{1+\frac{Km}{[S]} }

Let us consider an enzyme catalyses reaction E + S ⇄ ES → E + P

Where E, S, ES and P are enzyme, substrate, complex and product respectively.

The concentration of the complex [ES] = \frac{[E]0}{1+\frac{Km}{[S]} }, where K_{m} is the Michaelis constant.

[E]₀ and [S] is the initial concentration of enzyme and concentration of substrate respectively.    

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Hydrogen bonding is most often seen _____. see concept 2.3 (page 38) view available hint(s) hydrogen bonding is most often seen
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The density of atmosphere (measured in kilograms/meter3) on a certain planet is found to decrease as altitude increases (as meas
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The density at 1,291 km from the surface of the planet is

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3 years ago
Burning a compound of calcium, carbon and nitrogen in oxygen generates calcium oxide (CaO), carbon dioxide (CO2) and nitrogen di
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Answer:

CaCN₂

Explanation:

A compound of calcium, carbon and nitrogen CaₐCₓNₙ in oxygen will burning producing:

CaₐCₓNₙ + O₂ → aCaO + xCO₂ + nNO₂

Moles of the oxides CaO, CO₂, NO₂ are:

CaO: 3.106g ₓ (1 mole / 56.08g) = <em>0.0554 moles of CaO = moles of Ca</em>

CO₂: 2.439g ₓ (1mole / 44g) = <em>0.0554 moles CO₂ = moles C</em>

NO₂: 5.097g ₓ (1mole / 46g) = <em>0.111 moles NO₂ = moles N</em>

Empirical formula is the chemical formula that represents the simplest ratio of elements in a compound.

Having as basis 0.0554 moles (The lower number of moles):

0.0554 moles Ca / 0.0554 = 1 Ca

0.0554 moles C / 0.0554 = 1 C

0.111 moles N / 0.0554 = 2N

Thus, the compound CaₐCₓNₙ  has as empirical formula:

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3 0
4 years ago
If the volame ofa gas coetainer at 32°C changes froem 1.55 L to 753 ml, what will the final temperature be? Assume the pressure
motikmotik

Answer : The final temperature of gas will be, 149 K

Explanation :

Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T

or,

\frac{V_1}{V_2}=\frac{T_1}{T_2}

where,

V_1 = initial volume of gas = 1.55 L

V_2 = final volume of gas = 753 ml  = 0.753 L

T_1 = initial temperature of gas = 32^oC=273+32=305K

T_2 = final temperature of gas = ?

Now put all the given values in the above formula, we get the final temperature of the gas.

\frac{1.55L}{0.753L}=\frac{305K}{T_2}

T_2=149K

Therefore, the final temperature of gas will be, 149 K

7 0
4 years ago
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