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Citrus2011 [14]
3 years ago
10

Write the simple equation that describes the action of the enzyme catalase.

Chemistry
1 answer:
Nataly [62]3 years ago
5 0

Here we have to write a simple equation which describes the action of the enzyme catalase.

The equation is: The concentration of the complex [ES] = \frac{[E]0}{1+\frac{Km}{[S]} }

Let us consider an enzyme catalyses reaction E + S ⇄ ES → E + P

Where E, S, ES and P are enzyme, substrate, complex and product respectively.

The concentration of the complex [ES] = \frac{[E]0}{1+\frac{Km}{[S]} }, where K_{m} is the Michaelis constant.

[E]₀ and [S] is the initial concentration of enzyme and concentration of substrate respectively.    

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Which atom in the ground state has a partially filled second electron shell?
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Answer is Li
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A solution is made by adding 35.5 mL of concentrated hydrochloric acid ( 37.3 wt% , density 1.19 g/mL1.19 g/mL ) to some water i
erastova [34]

Answer:

1.73 M

Explanation:

We must first obtain the concentration of the concentrated acid from the formula;

Co= 10pd/M

Where

Co= concentration of concentrated acid = (the unknown)

p= percentage concentration of concentrated acid= 37.3%

d= density of concentrated acid = 1.19 g/ml

M= Molar mass of the anhydrous acid

Molar mass of anhydrous HCl= 1 +35.5= 36.5 gmol-1

Substituting values;

Co= 10 × 37.3 × 1.19/36.5

Co= 443.87/36.6

Co= 12.16 M

We can now use the dilution formula

CoVo= CdVd

Where;

Co= concentration of concentrated acid= 12.16 M

Vo= volume of concentrated acid = 35.5 ml

Cd= concentration of dilute acid =(the unknown)

Vd= volume of dilute acid = 250ml

Substituting values and making Cd the subject of the formula;

Cd= CoVo/Vd

Cd= 12.16 × 35.5/250

Cd= 1.73 M

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3 years ago
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