Answer:
88,88 % de O y 11,11 % de H
Explanation:
La composición porcentual se define como la masa que hay de cada mol de átomo en 100g. Las moles de agua en 100g son:
<em>Masa molar agua:</em>
2H = 2*1g/mol = 2g/mol
1O = 1*16g/mol = 16g/mol
Masa molar = 2 + 16 = 18g/mol
100g H2O * (1mol / 18g) = 5.556 moles H2O.
Moles de hidrógeno:
5.556 moles H2O * (2mol H / 1mol H2O) = 11.11 moles H
Moles Oxígeno = Moles H2O = 5.556 moles
La masa de hidrógeno es:
11.11mol * (1g/mol) 11.11g H
La masa de oxígeno es:
5.556 mol * (16g / 1mol) = 88.89g O
Así, el porcentaje de O es 88.89% y el de H es 11.11%. La opción correcta es:
<h3>88,88 % de O y 11,11 % de H</h3>
Answer:
it could be 25degrees c... not sure
Salt
Coffee
Flour
Oil
Pepper
Ethanol
(Etc.)
Answer:
0.75L
Explanation:
To get the number of liters of hydrogen gas produced, it is very essential to get the number of moles of hydrogen gas produced.
The number of moles of hydrogen gas produced is obtainable and accessible from
the number of moles of zinc reacted.
Hence, we will get the number of moles of zinc reacted at first. To get the number of moles of zinc reacted, we divide the mass of the zinc by the atomic mass of the zinc metal which is 65.38 amu
The number of moles of the zinc is thus: 2.2/65.38 which equals 0.03365 mole
From the equation of chemical reaction, it can be seen that one mole of zinc metal yielded one mole of hydrogen gas. Hence, it is expected that 0.03365mole of zinc will yield 0.03365mole of hydrogen gas.
Now, we proceed to get the volume of the hydrogen gas produced. We know quite well that at S.T.P a mole of a gas occupies a volume of 22.4L. Hence , 0.03365 mole will occupy a volume of 22.4 * 0.03365 which equals 0.75L
