Answer:
3. 3.45×10¯¹⁸ J.
4. 1.25×10¹⁵ Hz.
Explanation:
3. Determination of the energy of the photon.
Frequency (v) = 5.2×10¹⁵ Hz
Planck's constant (h) = 6.626×10¯³⁴ Js
Energy (E) =?
The energy of the photon can be obtained by using the following formula:
E = hv
E = 6.626×10¯³⁴ × 5.2×10¹⁵
E = 3.45×10¯¹⁸ J
Thus, the energy of the photon is 3.45×10¯¹⁸ J
4. Determination of the frequency of the radiation.
Wavelength (λ) = 2.4×10¯⁵ cm
Velocity (c) = 3×10⁸ m/s
Frequency (v) =?
Next, we shall convert 2.4×10¯⁵ cm to metre (m). This can be obtained as follow:
100 cm = 1 m
Therefore,
2.4×10¯⁵ cm = 2.4×10¯⁵ cm × 1 m /100 cm
2.4×10¯⁵ cm = 2.4×10¯⁷ m
Thus, 2.4×10¯⁵ cm is equivalent to 2.4×10¯⁷ m
Finally, we shall determine the frequency of the radiation by using the following formula as illustrated below:
Wavelength (λ) = 2.4×10¯⁷ m
Velocity (c) = 3×10⁸ m/s
Frequency (v) =?
v = c / λ
v = 3×10⁸ / 2.4×10¯⁷
v = 1.25×10¹⁵ Hz
Thus, the frequency of the radiation is 1.25×10¹⁵ Hz.
<h3>Further explanation</h3>
The basic oxide is an oxide-forming a base solution.
These oxides are mainly from group 1 alkaline and group 2-alkaline earth
If this oxide is dissolved in water it will form an alkaline solution
LO + H₂O --> L(OH)₂ ---> alkaline earth
L₂O + H₂O --> LOH --> alkaline
So the basic oxides : Na₂O and MgO
Na₂O + H₂O --> NaOH (sodium hydroxide, strong base)
MgO + H₂O --> Mg(OH)₂ (magnesium hydroxide, strong base)
The aqueous solution of CO₂ , obtained by dissolving CO₂ in water
CO₂ + H₂O --> H₂CO₃ (carbonic acid)
In general, basic oxide is obtained from metal oxide, while acid oxide is obtained from non-metal oxide
Answer:
Cool air moves down while hot air rises
Answer:
b. CH₂Cl₂ is more volatile than CH₂Br₂ because of the large dispersion forces in CH₂Br₂
Explanation:
CH₂Cl₂ is more volatile than CH₂Br₂ (b.p of CH₂Cl₂ = 39,6 °C; b.p of CH₂Br₂ = 96,95°C). Thus, c. and d. are FALSE
Dipole-dipole interactions in CH₂Cl₂ are greater than the dipole-dipole interactions in CH₂Br₂ because Cl is more electronegative that Br (Cl = 3,16; Br = 2,96). But this mean CH₂Cl₂ is less volatile than CH₂Br₂ but it is false.
There are large dispersion forces in CH₂Br₂ because Br has more electrons and protons than Cl. Large disperson forces mean CH₂Br₂ is less volatile than CH₂Cl₂ and it is true.
I hope it helps!
Answer:
P2 = 19.2atm
Explanation:
Initial pressure (P1) = 16atm
Initial temperature (T1) = 340K
Final temperature (T2) = 408K
Final pressure (P2) = ?
This question involves the use of pressure law
Pressure law states that the pressure of a fixed mass of gas is directly proportional to it's temperature provided that volume is kept constant.
Mathematically,
P = kT, k = P / T
Therefore,
P1 / T1 = P2 / T2 = P3 / T3 = ......=Pn / Tn
P1 / T1 = P2 / T2
We need to solve for P2
P2 = (P1 × T2) / T1
Now we can plug in the values and solve for P2
P2 = (16 × 408) / 340
P2 = 6528 / 340
P2 = 19.2atm
The final pressure (P2) of the gas is 19.2atm