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Zolol [24]
3 years ago
11

Predict the species that will be oxidized first if the following mixture of molten salts undergoes electrolysis:

Chemistry
1 answer:
Ede4ka [16]3 years ago
4 0

Answer:

Explanation:

the species that will be oxidized first will depend upon their oxidation potential .  

oxidation potential are given as follows

F⁻ =  -  2.87 V   , Br⁻ = - 1.09 V , Cl⁻ = -1.36 V, Mg⁺² = -2.37 V, Cu⁺² = +.34 V

Higher the oxidation potential , higher the tendency to be oxidised .

so Cu⁺²  is easiest to be oxidised  . F⁻ is to be oxidised most difficult.

The order from easiest to most difficult as follows

Cu⁺² >  Br⁻ > Cl⁻ > Mg⁺² > F⁻

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3. What is the energy of a photon whose frequency is 5.2 x 1015 Hz? Use the equation: E = hxv
anzhelika [568]

Answer:

3. 3.45×10¯¹⁸ J.

4. 1.25×10¹⁵ Hz.

Explanation:

3. Determination of the energy of the photon.

Frequency (v) = 5.2×10¹⁵ Hz

Planck's constant (h) = 6.626×10¯³⁴ Js

Energy (E) =?

The energy of the photon can be obtained by using the following formula:

E = hv

E = 6.626×10¯³⁴ × 5.2×10¹⁵

E = 3.45×10¯¹⁸ J

Thus, the energy of the photon is 3.45×10¯¹⁸ J

4. Determination of the frequency of the radiation.

Wavelength (λ) = 2.4×10¯⁵ cm

Velocity (c) = 3×10⁸ m/s

Frequency (v) =?

Next, we shall convert 2.4×10¯⁵ cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

2.4×10¯⁵ cm = 2.4×10¯⁵ cm × 1 m /100 cm

2.4×10¯⁵ cm = 2.4×10¯⁷ m

Thus, 2.4×10¯⁵ cm is equivalent to 2.4×10¯⁷ m

Finally, we shall determine the frequency of the radiation by using the following formula as illustrated below:

Wavelength (λ) = 2.4×10¯⁷ m

Velocity (c) = 3×10⁸ m/s

Frequency (v) =?

v = c / λ

v = 3×10⁸ / 2.4×10¯⁷

v = 1.25×10¹⁵ Hz

Thus, the frequency of the radiation is 1.25×10¹⁵ Hz.

8 0
3 years ago
ch question carries 2 mark. Time Remaining : 00 : 46 : 33 Some oxides are given below. (i)Na2O (ii)NO2 (iii) CO2 (iv) MgO a) Whi
cluponka [151]
<h3>Further explanation</h3>

The basic oxide is an oxide-forming a base solution.

These oxides are mainly from group 1 alkaline and group 2-alkaline earth

If this oxide is dissolved in water it will form an alkaline solution

LO + H₂O --> L(OH)₂ ---> alkaline earth

L₂O + H₂O --> LOH --> alkaline

So the basic oxides  : Na₂O and MgO

Na₂O + H₂O --> NaOH (sodium hydroxide, strong base)

MgO + H₂O --> Mg(OH)₂ (magnesium hydroxide, strong base)

The aqueous solution of CO₂ , obtained by dissolving CO₂ in water

CO₂ + H₂O --> H₂CO₃ (carbonic acid)

In general, basic oxide is obtained from metal oxide, while acid oxide is obtained from non-metal oxide

6 0
4 years ago
How does cooler air move in relation to warmer air?
ladessa [460]
Answer:
Cool air moves down while hot air rises
7 0
3 years ago
Which statement below matches the correct response with the proper reasoning when comparing the volatility of CH2Cl2 with CH2Br2
Nutka1998 [239]

Answer:

b. CH₂Cl₂ is more volatile than CH₂Br₂ because of the large dispersion forces in CH₂Br₂

Explanation:

CH₂Cl₂ is more volatile than CH₂Br₂ (b.p of CH₂Cl₂ = 39,6 °C; b.p of CH₂Br₂ = 96,95°C). Thus, c. and d. are FALSE

Dipole-dipole interactions in CH₂Cl₂ are greater than the dipole-dipole interactions in CH₂Br₂ because Cl is more electronegative that Br (Cl = 3,16; Br = 2,96). But this mean CH₂Cl₂ is less volatile than CH₂Br₂ but it is false.

There are large dispersion forces in CH₂Br₂ because Br has more electrons and protons than Cl. Large disperson forces mean CH₂Br₂ is less volatile than CH₂Cl₂ and it is true.

I hope it helps!

5 0
3 years ago
A sample of gas exerts a pressure of 16 atm at a temperature of 340 K. What is the pressure of the gas in atm if the temperature
gavmur [86]

Answer:

P2 = 19.2atm

Explanation:

Initial pressure (P1) = 16atm

Initial temperature (T1) = 340K

Final temperature (T2) = 408K

Final pressure (P2) = ?

This question involves the use of pressure law

Pressure law states that the pressure of a fixed mass of gas is directly proportional to it's temperature provided that volume is kept constant.

Mathematically,

P = kT, k = P / T

Therefore,

P1 / T1 = P2 / T2 = P3 / T3 = ......=Pn / Tn

P1 / T1 = P2 / T2

We need to solve for P2

P2 = (P1 × T2) / T1

Now we can plug in the values and solve for P2

P2 = (16 × 408) / 340

P2 = 6528 / 340

P2 = 19.2atm

The final pressure (P2) of the gas is 19.2atm

5 0
3 years ago
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