the formula for area of a rectangle is
Area = length x width
since both the length and the width of the rectangle lie on the same x and y axis, we can find the distance between the width and the distance between the length by subtracting
(-4,9) (-4,-3)
these points lie on the same x axis, so they create a vertical line
9-(-3) = 12
12 units is the distance between them
(-4,-3) (-1,-3)
these points lie on the same y axis, so they create a horizontal line
-1-(-4) = 3
3 units is the distance between them
now that we have the length and the width, we can find the area
A = 12 x 3
A = 36 units²
Answer:
see below
Step-by-step explanation:
Usually, we're concerned about the relationship of y to x. Here, the question is asking you to consider the relationship of x to y.
The easiest way to find the answer to this one is to check the given explanations to see which is true. You can pretty much ignore the first row of the table and just look at the second row where x=5 and y=15.
- it is NOT TRUE that x is 3 times y (5 is not 3 times 15)
- it is TRUE that x is 1/3 of y (5 is 1/3 of 15)
- it is NOT TRUE that x is 5 times y (5 is not 5 times 15)
- it is NOT TRUE that x is 1/5 of y (5 is not 1/5 of 15)
_____
If you know your multiplication tables, you know that 15 = 3×5, so ...
5 = 15/3
5 = (1/3) × 15
The relationship of these numbers should not be a mystery.
Answer:1 2/3
Step-by-step explanation:You subtract 5/3 by 3/3, then add 1 as the whole number
Answer:
feet
Step-by-step explanation:
In a 30-60-90 triangle, the ratios of the side lengths of the triangle is 
Where 1 is the shortest leg, root(3) is the longer leg, and 2 is the hypotenuse.
First we can set x equals to the length of the original pole, and so the shorter leg has a length of x/3 and using the ratio of side lengths, we can find that:

Solving for x, we find that

So the length of the original pole would be
feet
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9514 1404 393
Answer:
$7.14
Step-by-step explanation:
Let p, d, q represent the numbers of pennies, dimes, and quarters in the collection, respectively.
p + d + q = 45 . . . . . . . . there are 45 coins in the collection
2p +5 = q . . . . . . . . . . . . 5 more than twice the number of pennies
p + 4 = d . . . . . . . . . . . . . 4 more than the number of pennies
Substituting the last two equations into the first gives ...
p +(p +4) +(2p +5) = 45
4p = 36 . . . . . . . . . . . . . subtract 9
p = 9 . . . . . . . . . . . divide by 4
d = 9 +4 = 13
q = 2(9) +5 = 23
The value of the collection is ...
23(0.25) +13(0.10) +9(0.01) = 5.75 +1.30 +0.09 = 7.14
The coin collection is worth $7.14.