Answer:
168.57 mV
Explanation:
Initial magnetic flux = BA , B magnetic field and A is area of loop
= .35 x 3.14 x .37²
= .15 Weber
Final magnetic flux
= - .2 x 3.14 x .37²
= - .086 Weber
change in flux
.15 + .086
= .236 Weber
rate of change of flux
= .236 / 1.4
= .16857 V
= 168.57 mV
<h2><u>Hello </u><u>There</u></h2>
![\tt{Difference \: Between \: \underline\red {Horticulture} \: And \: \underline\green{Agriculture}}](https://tex.z-dn.net/?f=%20%5Ctt%7BDifference%20%5C%3A%20%20Between%20%5C%3A%20%20%20%5Cunderline%5Cred%20%7BHorticulture%7D%20%5C%3A%20%20And%20%5C%3A%20%20%20%5Cunderline%5Cgreen%7BAgriculture%7D%7D)
![\text{\underline\red {Horticulture}}](https://tex.z-dn.net/?f=%20%5Ctext%7B%5Cunderline%5Cred%20%7BHorticulture%7D%7D)
The Cultivation of Fruits, Vegetables and Flowers for domestic and international markets are called Horticulture.
![\text{\underline\green{Agriculture}}](https://tex.z-dn.net/?f=%20%5Ctext%7B%5Cunderline%5Cgreen%7BAgriculture%7D%7D)
It is science, art and occupation of cultivating the soil, producing crops and livestock. It is systematic and controlled use of living organisms and the environment to improve the human condition.
<h3>Hope This Helps</h3>
C. Negative force. The dog isn't going to learn that way.
Answer:
Jesus is in everyone's heart...
Just try to find him..:D
Answer with Explanation:
We are given that
Mass of box=35 kg
Coefficient of static friction between box and truck bed=0.202
Acceleration due to gravity=![9.8 m/s^2](https://tex.z-dn.net/?f=9.8%20m%2Fs%5E2)
a.We have to find the force by which the box accelerates forward.
Force by which box accelerates=![\mu mg=0.202\times 9.8\times 35](https://tex.z-dn.net/?f=%5Cmu%20mg%3D0.202%5Ctimes%209.8%5Ctimes%2035)
Force by which box accelerates=![62.286 N](https://tex.z-dn.net/?f=62.286%20N)
b.We have to find the maximum acceleration can the truck have before the box slides.
Force =friction force
![ma=\mu mg](https://tex.z-dn.net/?f=ma%3D%5Cmu%20mg)
![a=\mu g=9.8\times 0.202=1.9796 m/s^2](https://tex.z-dn.net/?f=a%3D%5Cmu%20g%3D9.8%5Ctimes%200.202%3D1.9796%20m%2Fs%5E2)
Hence, the truck can have maximum acceleration before the box slide=![1.9796 m/s^2](https://tex.z-dn.net/?f=1.9796%20m%2Fs%5E2)