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Basile [38]
3 years ago
7

PLEASE HELP ME ASAP!!! I need the answer to #9. If you can show work please do.

Chemistry
1 answer:
scoundrel [369]3 years ago
7 0

The correct answer would be 32/16s


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PLEASE HELP ASAP<br> Label the correct descriptors (volume, temperature, pressure, moles) *
Zanzabum

Explanation:

1. volume

2. pressure

3. moles

4. temperature

5. temperature

6. moles

7. pressure

8. volume

9. pressure

10. volume

5 0
2 years ago
What is 2KNO3 + 1H2CO3 = 1K2CO3+2HNO3 reaction type
Tema [17]
DR is the correct answer

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4 0
2 years ago
Which mixture can be classified as a homogeneous mixture?
kramer
Concrete is classified as a homogeneous mix
4 0
3 years ago
A compound is made of 6.00 grams of oxygen, 7.00 grams of nitrogen, and 20.00grams of hydrogen. Find the percent composition of
xxTIMURxx [149]

The percent composition of the compound.

A O-18.18%, N-21.21%, H-60.60%

<h3>Further explanation</h3>

Given

6.00 grams of oxygen,

7.00 grams of nitrogen,

20.00 grams of hydrogen.

Required

The percent composition

Solution

Total mass :

= mass of O + mass of N + mass of H

= 6 + 7 + 20

= 33 g

% O = 6/33 x 100%= 18.18%

% N = 7/33 x 100%=21.21%

% H = 20/33 x 100% = 60.6 %

6 0
2 years ago
Sodium phosphate is added to a solution that contains 0.0070 M aluminum nitrate and 0.052 M calcium chloride. The concentration
boyakko [2]

Answer:

The answer to the question is;

The first ion to precipitate out is the Al³⁺ ion and the concentration of the Al³⁺ ion when the Ca²⁺ ion begins to precipitate is 1.12 × 10⁻⁵ M.

Explanation:

To solve the question, we note that

aluminum nitrate, Al(NO₃)₃ will dissociate as follows

Al(NO₃)₃ → Al³⁺ (aq) + 3NO₃⁻ (aq)

Therefore when sodium phosphate is added to a solution that contains aluminum nitrate  we have the following system  of aluminium phosphate which is

AlPO₄(s) ⇄ Al³⁺(aq) + PO₄³⁻(aq)

The solubility product for the above reaction is

Ksp = [Al³⁺][PO₄³⁻] = 9.84×10⁻²¹

The solubility product for calcium phosphate is expressed as

Ca₃(PO₄)₂(s) ⇄ 3 Ca²⁺(aq) + 2 PO₄³⁻(aq)

With Ksp =  [Ca²⁺]³[PO₄³⁻]² = 2.07×10⁻³³

From the solubility product, we can find the concentration of [PO₄³⁻] at which precipitation starts as follows

The phosphate concretion for Al³⁺ when precipitation starts is

[PO₄³⁻] = \frac{K_{sp}}{[Al^{3+}]}= 9.84×10⁻²¹ / 0.007 = 1.406×10⁻¹⁸ M

The phosphate concretion for Ca²⁺ when precipitation starts is

[PO₄³⁻] =\sqrt{\frac{K_{sp}}{[Ca^{2+}]^2}}  = \sqrt{\frac{2.07\times10^{-33}}{[0.052]^2}} = 8.75×10⁻¹⁶ M

(Aluminium phosphate precipitates out first)

The reaction favors the precipitation of the aluminum phosphate first due to the lower concentration of the [PO₄³⁻]  ions in the [Al³⁺][PO₄³⁻] system which  is lower than the relative [PO₄³⁻] in the [Ca²⁺]³[PO₄³⁻]².

Therefore, the more sodium phosphate added serves to precipitate the remaining aluminium phosphate.

The process continues and the concentration of Al³⁺ decreases as more precipitates form. The process continues until the equilibrium conditions satisfies the precipitation threshold level for the calcium phosphate system concentration whereby the concentration of the Al³⁺ in the solution is given by.

[Al³⁺] = \frac{K_{sp}}{[PO_4^{3-}]} = \frac{9.84\times 10^{-21}}{8.75\times 10^{-16}}  = 1.12 × 10⁻⁵ M

Therefore the concentration of this aluminium ion when the calcium ion begins to precipitate =  1.12 × 10⁻⁵ M.

8 0
3 years ago
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