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MrRissso [65]
3 years ago
9

4/5 ÷ 7/6 + 2/7 ∙2 1/5

Mathematics
1 answer:
Aleksandr [31]3 years ago
4 0
<h2>The value of \dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5} =\dfrac{8}{7}</h2>

Step-by-step explanation:

We have,

\dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5}

To find, the value of \dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5} = ?

∴ \dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5}

=\dfrac{4}{5}\times \dfrac{6}{7} +\dfrac{2}{7}.\dfrac{8}{5}

=\dfrac{24}{35} +\dfrac{16}{35}

Taking LCM of denominator, we get

=\dfrac{24+16}{35}

=\dfrac{40}{35}

Dividing numerator and denominator by 5, we get

=\dfrac{8}{7}

∴ The value of \dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5} =\dfrac{8}{7}

Hence, the value of \dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5} is equal to \dfrac{8}{7} .

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Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.

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Based on the shape of a mound, the law of cosines can be used.

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Find out more solving for distance at brainly.com/question/10739348

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