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posledela
3 years ago
15

Holding temperature and pressure constant, what is the most important feature in determining the phase of a given organic compou

nd?
Chemistry
2 answers:
exis [7]3 years ago
7 0

Answer:

The type of intermolecular forces present.

Explanation:

Intermolecular forces are forces that hold a substance together in a particular star of matter. There are three states of matter; solid liquid and gas. What determines whether or not an organic substance will be found in a particular state of matter at constant temperature and pressure is the nature of intermolecular forces present.

For instance, alkanoic acids mostly exist as liquids due to intermolecular hydrogen bonding. The alkanes are mostly gases due to weak van der Waals forces present.

Leni [432]3 years ago
3 0
Holding temperature and pressure constant <span>the most important feature in determining the phase of a given organic compound is pressure. ransfers of organic compounds between phases are controlled by molecular interactions (intermolecular bonding) in the two phases between which transfer is occurring. This is governed by temperature and pressure</span>
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What type of energy does a cup sitting on a table have? Why?
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POTENTIAL ENERGY

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3 years ago
Which compound is expected to exhibit hydrogen bonding forces?
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3 years ago
When heated to 150 ºC, CuSO4.5 H2O loses its water of hydration as gaseous H2O. A 2.50 g sample of the compound is placed in a s
Katyanochek1 [597]

Answer:

Water pressure 0.5 atm

Total Pressure= 2.27  atm

Explanation:

To answer this problem, one has to realize that there are two processes that increase the temperature of the sealed vessel.

First, the dry air in the sealed vessel will be heated which will cause its pressure to increase and it can be determined by the equation:

P₁ x T₂   = P₂ x T₁  ∴  P₂ =  P₁ x T₂ / T₁

For the second process, we have an amount of n moles of water which will be released when the copper sulfate is heated. In this case, to determine the value of the the water gas we will use the gas law:

   PV = nRT  ∴ P =  nRT/V

n will we calculated from the quantity of sample.

2.50 g  CuSo₄ 5H₂O x  1 mol/ 249.69 g = 0.01 mol CuSo₄ 5H₂O

the amount water of hydration is

= 0.01 mol CuSo₄ 5H₂O * 5 mol H₂O / 1 mol CuSo₄ 5H₂O

= 0.05 mo H₂O

pressure of dry air at the final temperature,

P₂ = 1 atm x 500 K/ 300 K = 1.67 atm

Pressure of water :

P (H₂O) 0.05 mol x 0.08206 Latm/kmol x 500 K/ 4 L = 0.5 atm

∴ Total Pressure =  1.67 atm

H2O Pressure = 0.5 atm

5 0
3 years ago
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