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posledela
3 years ago
15

Holding temperature and pressure constant, what is the most important feature in determining the phase of a given organic compou

nd?
Chemistry
2 answers:
exis [7]3 years ago
7 0

Answer:

The type of intermolecular forces present.

Explanation:

Intermolecular forces are forces that hold a substance together in a particular star of matter. There are three states of matter; solid liquid and gas. What determines whether or not an organic substance will be found in a particular state of matter at constant temperature and pressure is the nature of intermolecular forces present.

For instance, alkanoic acids mostly exist as liquids due to intermolecular hydrogen bonding. The alkanes are mostly gases due to weak van der Waals forces present.

Leni [432]3 years ago
3 0
Holding temperature and pressure constant <span>the most important feature in determining the phase of a given organic compound is pressure. ransfers of organic compounds between phases are controlled by molecular interactions (intermolecular bonding) in the two phases between which transfer is occurring. This is governed by temperature and pressure</span>
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Tungsten fits best into which category?
nordsb [41]

Answer:

B. Element

Explanation:

Tungsten is an chemical element

4 0
3 years ago
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What is Δn for the following equation in relating Kc to Kp?CH4(g) + H2O(g) ↔ CO(g) + 3 H2(g)-120-3-2
Sindrei [870]

Answer: Δn for the following equation in relating Kc to Kp is 2.

Explanation:

The balanced chemical equation is:

CH_4(g)+H_2O(g)\rightleftharpoons CO(g)+3H_2(g)

Relation of K_p with K_c is given by the formula:

K_p=K_c(RT)^{\Delta n_g}

Where,

K_p = equilibrium constant in terms of partial pressure

K_c = equilibrium constant in terms of concentration

R = Gas constant

T = temperature

\Delta n_g = change in number of moles of gas particles = n_{products}-n_{reactants}=4-2=2

Putting values in above equation, we get:

K_p=K_c\times (RT)^{2}

Thus the value of Δn for the following equation in relating Kc to Kp is 2.

5 0
3 years ago
Calculate the cell potential for the following reaction as written at 25.00 °C, given that [Cr2 ] = 0.892 M and [Fe2 ] = 0.0150
Effectus [21]

<u>Given:</u>

Concentration of Cr2+ = 0.892 M

Concentration of Fe2+ = 0.0150 M

<u>To determine:</u>

The cell potential, Ecell

<u>Explanation:</u>

The half cell reactions for the given cell are:

Anode: Oxidation

Cr(s) ↔ Cr2+(aq) + 2e⁻                E⁰ = -0.91 V

Cathode: Reduction

Fe2+ (aq) + 2e⁻ ↔ Fe (s)              E⁰ = -0.44 V

------------------------------------------

Net reaction: Cr(s) + Fe2+(aq) ↔ Cr2+(aq) + Fe(s)

E°cell = E°cathode - E°anode = -0.44 - (-0.91) = 0.47 V

The cell potential can be deduced from the Nernst equation as follows:

Ecell = E°cell - (0.0591/n)log[Cr2+]/[Fe2+]

Here, n = number of electrons = 2

Ecell = 0.47 - 0.0591/2 * log[0.892]/[0.0150] = 0.418 V

Ans: The cell potential is 0.418 V

8 0
3 years ago
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This part of the plant cell turns sunlight into food. It is called a
frez [133]

Answer:

Chloroplast

GOOD LUCK!!!

8 0
3 years ago
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CH4(g)+O2(g)→CO2(g)+H2O(g). What mass of water is produced from the complete combustion of 5.00×10−3 g of methane?
bixtya [17]

Answer:

1gram of water

Explanation:

First balance the equation

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Ratio is 1:2

500×10-3what about 2?

500×10-3×2=1g

1g of water

4 0
3 years ago
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