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3 years ago

Who devised the scientific naming system for the classification of living things.

Chemistry

2 answers:

Juli2301 [7.4K]3 years ago

4 0

Carolus Linnaeus
have a nice day

Marrrta [24]3 years ago

3 0

Carolus Linnaeus was the one Who devised the scientific naming system for the classification of living things.
hope that helped!

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Answer:

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3 years ago

Four gases were combined in a gas cylinder with these partial pressures: 3. 5 atm N2, 2. 8 atm O2, 0. 25 atm Ar, and 0. 15 atm H

aksik [14]

The total pressure of the gas has been 11.9 atm.

The partial pressure has been the pressure exerted by the individual gas in the mixture.

According to the Dalton's law of Partial pressure, the pressure of the gas has been the sum of the partial pressure of each gas in the mixture.

<h3 /><h3>Computation for the pressure of gas</h3>

The given gas has partial pressure of Nitrogen, $P_{N_2}=3.5\;\rm atm$

The partial pressure of Oxygen, $P_{O_2}=8\;\rm atm$

The partial pressure of Argon, $P_{Ar}=0.25\;\rm atm$

The partial pressure of Helium, $P_{He}=0.15\;\rm atm$

The total pressure, (P) of the gas has been given as:

$P=P_{N_2}\;+\;P_{O_2}\;+\;P_{Ar}\;+\;P_{He}\\
P=3.5\;+8\;+\;0.25\;+\;0.15\;\text{atm}\\
P=11.9\;\rm atm$

The total pressure of the gas has been 11.9 atm.

Learn more about the vapor pressure, here:

brainly.com/question/25356241

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3 years ago

When you want to dilute a solution, what

GREYUIT [131]

Answer:

Dilution is the prosess where a solution is added more of the solvent to decrease the concentration of the solute. In dilution, the amount of solute does not change, the number of moles are the same before and after dilution.

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3 years ago

For a solution of acetic acid (CH3COOH) to be called “vinegar,” it must contain 5.00% acetic acid by mass. If a vinegar is made

emmasim [6.3K]

Answer:

M = 0.838 M

Explanation:

1) Data:

a) Acetic acid CH₃COOH

b) molar mass of CH₃COOH: 60.052 g/mol

c) %: = 5.00%

d) d = 1.006 g/ml

e) M = ?

2) Formulae:

a) M = n of solute / V of solution in liters

b) n = mass in grams / molar mass

c) % = (mass of solute / mass of solution)×100

d) d = mass / volume

3) Solution:

a) Assume a basis

V = 1 liter of solution

b) Calculate the mass of that basis (1 liter of solution)

d = mass / V ⇒ mass = d × V

mass = 1.006 g/ml × 1 liter × 1,000 ml/liter = 1006 g

c) Calculate the mass of solute

% = (mass of solute / mass of solution ) × 100 ⇒

mass of solute = % × mass of solution / 100 = 5.00% × 1,006 g / 100

mass of solute = 50.3 g

d) Calculate the number of moles of solute

n = mass in grams / molar mass = 50.3 g / 60.052 g/mol = 0.838 mol

e) Calculate molarity

M = n / V in liter = 0.838 mol / 1 liter = 0.838 M ← answer

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3 years ago

Please help me ASAP I’ll mark Brainly

sammy [17]

Answer:

1. Vacuole

2. chloroplast

3. Nucleus

4. Plasma membrane - cell membrane

5. Vacuole (same as #1 ?) could be vesicle

Explanation:

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3 years ago