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3 years ago

100 K = _____ -173°C 0°C 100°C 373°C

Chemistry

2 answers:

Hunter-Best [27]3 years ago

7 0

Answer : The correct option is, $-173^oC$

Explanation :

The conversion used for the temperature from Kelvin to degree Celsius is:

$K=273+^oC$

where,

K = temperature in Kelvin = 100 K

$^oC$ = temperature in degree Celsius = ?

Now put the value in the above conversion, we get the temperature in degree Celsius.

$100=273+^oC$

$^oC=100-273$

$^oC=-173$

Therefore, the temperature in degree Celsius is, $-173^oC$

Dahasolnce [82]3 years ago

6 0

100 k= -173°c...............

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Elza [17]

Answer:

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3 years ago

A 45-g aluminium spoon(specific heat 0.80 / J/gdegree Celsius) at 24 degree celsius is placed in 180 ml(180 grams) of coffee at

Vlad [161]

Explanation:

a) The amount of heat released by coffee will be absorbed by aluminium spoon.

Thus, $heat_{absorbed}=heat_{released}$

To calculate the amount of heat released or absorbed, we use the equation:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

Also,

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ ..........(1)

where,

q = heat absorbed or released

$m_1$ = mass of aluminium = 45 g

$m_2$ = mass of coffee = 180 g

$T_{final}$ = final temperature = ?

$T_1$ = temperature of aluminium = $24^oC$

$T_2$ = temperature of coffee = $85^oC$

$c_1$ = specific heat of aluminium = $0.80J/g^oC$

$c_2$ = specific heat of coffee= $4.186 J/g^oC$

Putting all the values in equation 1, we get:

$45 g\times 0.80J/g^oC\times (T_{final}-24^oC)=-[180 g\times 4.186J/g^oC\times (T_{final}-83^oC)]$

$T_{final}=80.30^oC$

80.30 °C is the final temperature.

b) Energy flows from higher temperature to lower temperature.Whenever two bodies with different energies and temperature come in contact. And the resulting temperature of both bodies will less then the body with high temperature and will be more then the body with lower temperature.

So, is our final temperature of both aluminium and coffee that is 80°C less than initial temperature of coffee and more than the initial temperature of the aluminum.

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2 years ago

URGENT PLEASE HELP!!!

mote1985 [20]

Even though two grams seemed to disappear or vanish, the law of conversation of mass still holding true. Mercuric oxide, when heated, forms a gas of mercury and oxygen. During the investigation, some gas could have escaped or evaporated.

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2 years ago

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3 years ago

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Volgvan

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<h3>Data obtained from the question </h3>

Energy (cal) = 6.85×10⁵ cal
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<h3>Conversion scale </h3>

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<h3>How to convert 6.85×10⁵ cal to kilojoules</h3>

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2 years ago