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marissa [1.9K]
3 years ago
14

100 K = _____ -173°C 0°C 100°C 373°C

Chemistry
2 answers:
Hunter-Best [27]3 years ago
7 0

Answer : The correct option is, -173^oC

Explanation :

The conversion used for the temperature from Kelvin to degree Celsius is:

K=273+^oC

where,

K = temperature in Kelvin = 100 K

^oC = temperature in degree Celsius = ?

Now put the value in the above conversion, we get the temperature in degree Celsius.

100=273+^oC

^oC=100-273

^oC=-173

Therefore, the temperature in degree Celsius is, -173^oC

Dahasolnce [82]3 years ago
6 0
100 k= -173°c...............
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Need help on this question asap pleasee I would really appreciate it
Elza [17]

Answer:

See Explanation

Explanation:

An endothermic reaction is one in which energy is absorbed and the change in enthalpy for the reaction is positive.

If we look at the reaction 2HgO + 45kcal ----> 2Hg + O2; we will notice that

i) 45kcal of energy was taken in (absorbed) for the reaction to occur

ii) The value of the reaction enthalpy is positive

For these two reasons, the reaction is an endothermic reaction as written.

6 0
3 years ago
A 45-g aluminium spoon(specific heat 0.80 / J/gdegree Celsius) at 24 degree celsius is placed in 180 ml(180 grams) of coffee at
Vlad [161]

Explanation:

a) The amount of heat released by coffee will be absorbed by aluminium spoon.

Thus, heat_{absorbed}=heat_{released}

To calculate the amount of heat released or absorbed, we use the equation:  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

Also,

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]    ..........(1)

where,

q = heat absorbed or released

m_1 = mass of aluminium = 45 g

m_2 = mass of coffee = 180 g

T_{final} = final temperature = ?

T_1 = temperature of aluminium = 24^oC

T_2 = temperature of coffee = 85^oC

c_1 = specific heat of aluminium = 0.80J/g^oC

c_2 = specific heat of coffee= 4.186 J/g^oC

Putting all the values in equation 1, we get:

45 g\times 0.80J/g^oC\times (T_{final}-24^oC)=-[180 g\times 4.186J/g^oC\times (T_{final}-83^oC)]

T_{final}=80.30^oC

80.30 °C is the final temperature.

b) Energy flows from higher temperature to lower temperature.Whenever two bodies with different energies and temperature come in contact. And the resulting temperature of both bodies will less then the body with high temperature and will be more then the body with lower temperature.

So, is our final temperature of both aluminium and coffee that is 80°C less than initial temperature of coffee and more than the initial temperature of the aluminum.

8 0
2 years ago
URGENT PLEASE HELP!!!
mote1985 [20]
Even though two grams seemed to disappear or vanish, the law of conversation of mass still holding true. Mercuric oxide, when heated, forms a gas of mercury and oxygen. During the investigation, some gas could have escaped or evaporated.
5 0
2 years ago
Read 2 more answers
Johanna makes the table below to organize her notes about centripetal forces. Which type of force should she place in the cell m
Valentin [98]

<u>Answer:</u> The correct answer is Option 2.

<u>Explanation:</u>

Centripetal force is defined as the force that acts on a body moving in a circular path and is directed towards the center around which the body is moving.

Mathematically,

F_c=\frac{mv^2}{r}

Where,

F_c = centripetal force

m = mass of the object

v = tangential velocity

r = radius of the path

From the above relation, X corresponds to the radius and Y corresponds to the tangential velocity.

Hence, the correct answer is option C.

3 0
3 years ago
Read 2 more answers
Duncan takes a break from studying and goes to the gym to swim laps If swimming burns amount of time ? 85 * 10 ^ 5 cal per hour
Volgvan

When 6.85×10⁵ cal is converted to kilojoules, the result obtained is 2866.04 KJ

<h3>Data obtained from the question </h3>
  • Energy (cal) = 6.85×10⁵ cal
  • Energy (KJ) =?

<h3>Conversion scale </h3>

1 cal = 0.004184 KJ

<h3>How to convert 6.85×10⁵ cal to kilojoules</h3>

1 cal = 0.004184 KJ

Therefore,

6.85×10⁵ cal = 6.85×10⁵ × 0.004184

6.85×10⁵ cal = 2866.04 KJ

Thus, 6.85×10⁵ cal is equivalent to 2866.04 KJ

Learn more about conversion:

brainly.com/question/2139943

6 0
2 years ago
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