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Sergio [31]
3 years ago
7

For a solution of acetic acid (CH3COOH) to be called “vinegar,” it must contain 5.00% acetic acid by mass. If a vinegar is made

up only of acetic acid and water, what is the molarity of acetic acid in the vinegar? The density of vinegar is 1.006 g/mL
Chemistry
1 answer:
emmasim [6.3K]3 years ago
6 0

Answer:

  • M = 0.838 M

Explanation:

<u>1) Data:</u>

<u />

a) Acetic acid CH₃COOH

b) molar mass of CH₃COOH: 60.052 g/mol

c) %: = 5.00%

d) d = 1.006 g/ml

e) M = ?

<u>2) Formulae:</u>

a) M = n of solute / V of solution in liters

b) n = mass in grams / molar mass

c) % = (mass of solute / mass of solution)×100

d) d = mass  / volume

<u>3) Solution:</u>

a)<u> Assume a basis </u>

  • V = 1 liter of solution

b) <u>Calculate the mass of that basis (1 liter of solution)</u>

  • d = mass / V ⇒ mass = d × V
  • mass = 1.006 g/ml × 1 liter × 1,000 ml/liter = 1006 g

c) <u>Calculate the mass of solute</u>

<u />

  • % = (mass of solute / mass of solution ) × 100 ⇒

        mass of solute = % × mass of solution / 100 = 5.00% × 1,006 g / 100

        mass of solute = 50.3 g

d) <u>Calculate the number of moles of solute</u>

<u />

  • n = mass in grams / molar mass = 50.3 g / 60.052 g/mol =  0.838 mol

e) <u>Calculate molarity</u>

  • M = n / V in liter = 0.838 mol / 1 liter = 0.838 M ← answer
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