9514 1404 393
Answer:
(a) In triangles APD and BPC; AD = BC
Step-by-step explanation:
We're not concerned with triangle APB, eliminating the last 2 choices.
We're not concerned with sides AP and BP, as they're not sides of the square, eliminating the second choice.
The choice that makes any sense in the proof is ...
In triangles APD and BPC; AD = BC
Answer:
16
Step-by-step explanation:
grater than 13 less than 20
14,15,16,17,18,19
6 ones
16
Answer:
Let O be the center of a circle whose radius is r cm , in which AB= 14 cm long
cord is at a distanceof 24 cm from O. Draw a perpendicular OD on AB , thus ,
OD= 24 cm.
In right angled triangle. ODB
OB^2 = OD^2+ DB^2
r^2 =(24)^2+(AB/2)^2 = 576+(14/2)^2
r^2 = 576+ 49=625
r = √625. =25 cm. Answer.
Answer:
multiplying 2 then dividing
Step-by-step explanation:
When it comes to laplace equations, there are transformation equations to follow. Generally, when you want to transform a laplace equation, you change the equation from f(t) to F(s). If you do the reverse, it is called the reverse laplace equation.
Based on the given, the useful transformation equation is shown in the attached picture.
When the term is s^2, that must mean that the equation is 1!/s^(1+1) to yield 1/s^2. This means that n=1. Taking the reciprocal s^2 must be equal to 1/t. Thus, for the first term, -11s^2 is equal to -11/t. For the second term, n must be equal to 6 so that 6!/s^(6+1) would yield 720/s^7. Thus, 720s^7 is equal to 1/t^6.
Hence, the transformed equation is
-11/t - 1/t^6