50 mL of soda in a soda can exerts ____ 50 mL of soda in a 1L bottle.

A 5g block rests on a rough horizontal table a rope attached to the block is pulled with a force of 11N to the left as a result

mr Goodwill [35]

Complete Question:

A 5 g block rests on a rough horizontal table. A rope is attached to the block and is pulled with a force of 11 N to the left. As a result, the block accelerates at 2 m/s^2. What is the kinetic friction between the block and the table?

Correct Answer:

The kinetic frictional force between the block and the rough surface is 10.99 N towards the right side.

$F_{net}$ = - 0.01 N is the resulting net force causing an acceleration of $2\ m/s^2$ to the left

Explanation:

According to the first law of motion by Newton, any object can be moved only when an unbalanced force acts on the object. As the block is placed on a rough horizontal table, then the applied force should be greater than the kinetic frictional force between the object and the rough surface, in order to move that block.

So, it is known that the net force acting on the block will be the difference between the force acting on the object due to the rope and the frictional force acting on the object.

$F_{net} = F_{rope} -F_{friction}$

So, the force acting on the block due to rope is given as 11 N. The net force should be equal to the product of mass and acceleration of the object, as per Newton's second law of motion. As the mass of the block is 5 g and the acceleration is given as $2\ m/s^2$ .

$F_{net} = Mass * Acceleration = \frac{5}{1000} * -2 = -0.01 N$

Since, the net force and the force due to rope is acting opposite to the gravitational force ,

-0.01 = -11 - Frictional force

Frictional force = -11 + 0.01 = -10.99 N

Thus, the kinetic frictional force between the block and the rough surface is 10.99 N towards the right side.

$F_{net}$ = - 0.01 N is the resulting net force causing an acceleration of $2\ m/s^2$ to the left

7 0

3 years ago

6) CHALLENGE PROBLEM: In searching the bottom of a pool at night, a

sveticcg [70]

Answer:

7.08 m

Explanation:

(If we ignore the refraction of light)

There will form two triangles one at the top of pool (torch, edge of pool and point of incidence at top of pool) and one at the bottom of pool (torch, edge of pool and point of incidence at bottom of pool) .

first triangle at the top of pool (torch, edge of pool and point of incidence at top of pool)

First we need to find the angle of incidence:

Height = perpendicular = 1.3 m

Point of incidence = base= 2.5 m

now

tan∅= perpendicular / base

∅= tan⁻¹ (perpendicular / base)

∅=tan⁻¹ (1.3/2.5)

∅= 27.5°

Now 2nd triangle at the bottom of pool (torch, edge of pool and point of incidence at bottom of pool)

Height = perpendicular = 1.3 m + 2.1 m= 3.4 m (torch height + depth of pool)

∅= 27.5°

Spot of light hit bottom of pool= base=?

tan∅ = perpendicular / base

base = perpendicular / tan∅

base = 3.4/tan(27.5°)

base= 7.08 m

Spot of light hit bottom of pool= base= 7.08 m

5 0

4 years ago

For the wave of light you generated in the Part B, calculate the amount of energy in 1.0 mol of photons with that same frequency

Angelina_Jolie [31]

Answer:

2.7 J

Explanation:

The energy of one photon is given by

$E=hf$

where

h is the Planck constant

f is the frequency

For the photons in this problem,

$f=6.8\cdot 10^9 Hz$

So the energy of one photon is

$E_1=(6.63\cdot 10^{-34})(6.8\cdot 10^9 )=4.5\cdot 10^{-24} J$

The number of photons contained in 1.0 mol is

$N_A = 6.022\cdot 10^{23} mol^{-1}$ (Avogadro number)

So the total energy of $N_A$ photons contained in 1.0 mol is

$E=N_A E_1 =(6.022\cdot 10^{23})(4.5\cdot 10^{-24})=2.7 J$

3 0

3 years ago

How many planets are there in the milky way galaxy?

Basile [38]

There are eight planets in the milky way galaxy

8 0

4 years ago

What kind of friction exists between solid objects moving in water?

Stels [109]

The best and most correct answer among the choices provided by the question is drag.

Drag kind of friction exists between solid objects moving in water.

Hope my answer would be a great help for you.
If you have more questions feel free to ask here at Brainly.

6 0

3 years ago