Work formula:
![W = Fd\cos(\theta)](https://tex.z-dn.net/?f=W%20%3D%20Fd%5Ccos%28%5Ctheta%29)
F = 50N, d = 1.0 m
When you lift something straight up, the angle of the force is 90º
cos(90º) is 0, so there's no work done when you lift the microwave off the ground
![W = (50N)(1.0)(0) = 0](https://tex.z-dn.net/?f=W%20%3D%20%2850N%29%281.0%29%280%29%20%3D%200)
F = 50N, d = 1.0 m
When you push the microwave, the angle is 0º and cos(0º) is 1. So there is work done here:
![W = (50 N)(1.0m)(1)](https://tex.z-dn.net/?f=W%20%3D%20%2850%20N%29%281.0m%29%281%29)
![W = 50](https://tex.z-dn.net/?f=W%20%3D%2050)
total work = 50 joules
Hello,
Here is your answer:
The proper answer to this question is "because of there substantial size the rock rests on another rock which keeps it balanced".
If you need anymore help feel free to ask me!
Hope this helps!
Answer:
145 m
Explanation:
Given:
Wavelength (λ) = 2.9 m
we know,
c = f × λ
where,
c = speed of light ; 3.0 x 10⁸ m/s
f = frequency
thus,
![f=\frac{c}{\lambda}](https://tex.z-dn.net/?f=f%3D%5Cfrac%7Bc%7D%7B%5Clambda%7D)
substituting the values in the equation we get,
![f=\frac{3.0\times 10^8 m/s}{2.9m}](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B3.0%5Ctimes%2010%5E8%20m%2Fs%7D%7B2.9m%7D)
f = 1.03 x 10⁸Hz
Now,
The time period (T) = ![\frac{1}{f}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf%7D)
or
T =
= 9.6 x 10⁻⁹ seconds
thus,
the time interval of one pulse = 100T = 9.6 x 10⁻⁷ s
Time between pulses = (100T×10) = 9.6 x 10⁻⁶ s
Now,
For radar to detect the object the pulse must hit the object and come back to the detector.
Hence, the shortest distance will be half the distance travelled by the pulse back and forth.
Distance = speed × time = 3 x 10^8 m/s × 9.6 x 10⁻⁷ s) = 290 m {Back and forth}
Thus, the minimum distance to target =
= 145 m