Which of the following describes the importance of cyanobacteria to early Earth atmosphere formation?

When I wave a charged golf tube at the front of the classroom with a frequency of two oscillations per second, I produce an elec

solmaris [256]

To solve this problem it is necessary to apply the concepts related to Wavelength depending on the frequency and speed of light.

The equation that meets these parameters is given by

$\lambda = \frac{c}{f}$

Where,

c = Speed of light

$\lambda = Wavelength$

f = Frequency

Our values are given as

$c = 3*10^8m/s \rightarrow$ velocity of light in free space

f = 2Hz

Replacing we have that

$\lambda = \frac{c}{f}\\\lambda = \frac{3*10^8}{2}\\\lambda = 1.5*10^8m$

Therefore the correct answer is B.

3 0

2 years ago

wo ships, one 200200 metres in length and the other 100100 metres in length, travel at constant but different speeds. When trave

shutvik [7]

Answer:

The speed of the faster ship is 22.5 m/s

Explanation:

The length of the ships are;

Ship 1 = 200 m

Ship 2 = 100 m

The time it takes for the ships to completely cross each other when travelling in opposite directions = 10 seconds

The time it takes both ships to cross each other when travelling in the same direction = 25 seconds

Let x represent the speed of the first ship, ship 1, and y represent the speed of the second ship, ship, 2, we have;

(x + y) × 10 = 200 + 100 = 300

10·x + 10·y = 300...(1)

(x - y) × 20 = 200 + 100 = 300

20·x - 20·y = 300...(2)

Multiply equation (1) by 2, to get;

(x + y) × 10 × 2 = 300 × 2

20·x + 20·y = 600...(3)

Adding equation (1) to equation (3) gives;

20·x + 20·y + 20·x - 20·y = 600 + 300

40·x = 900

x = 900/40 = 22.5

x = 22.5

The speed of the first ship, ship 1 = x = 22.5 m/s

From equation (1), we have;

10·x + 10·y = 300

y = (300 - 10·x)/10 = (300 - 10×22.5)/10 = 7.5

y = 7.5

The speed of the second ship, ship 2 = y = 7.5 m/s

Therefore, the faster ship is ship 1 with a speed of 22.5 m/s

7 0

2 years ago

The Henry's law constant for CO2 is 3.6 ✕ 10−2 M/atm at 25°C. What pressure (in atm) of carbon dioxide is needed to maintain a C

xeze [42]

To solve this problem we will use Henry's law. This law states that at a constant temperature, the amount of gas dissolved in a liquid is directly proportional to the partial pressure exerted by that gas on the liquid. Mathematically it is formulated as follows:

$C = K_H*P$

Where,

$K_H$ = Henry's constant for C02 at 25°C is equal to $3.6*10^{-2}M/atm$

C = Gas concentration is 0.19M

Replacing we have,

$0.19 M = (3.6*10^-2 M/atm)*P$

$P = 5.277 atm$

Therefore the pressure of carbon dioxide is 5.277 atm

6 0

2 years ago

What are the four planets that orbit closets to the sun

Elden [556K]

Answer:

Explanation:The four closest to the sun — Mercury, Venus, Earth and Mars — are the terrestrial planets. They have rocky surfaces enclosed by relatively shallow atmospheres.

8 0

2 years ago

URGENT! PLEASE ANSWER!!

Marrrta [24]

Answer:

C

Explanation:

The answer is obvious from the given figure

7 0

3 years ago