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3 years ago

Which of the following is likely the best electrical insulator

Physics

1 answer:

Vesnalui [34]3 years ago

5 0

Is a vaccum cleaner there is no choices so here is one

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Un ciclista recorre una pista recta de ida y vuelta, en este recorrido:

Elena-2011 [213]

Answer:

a) falso

b) verdadero

c) falso

d) falso

e) verdadero

Explanation:

A) FALSO: la distancia recorrida es independiente del punto de partida y del punto de llegada

B) VERDADERO: para que el ciclista recorra la pista de ida y vuelta es necesario que su velocidad cambie, por lo tanto la aceleración es diferente de cero.

C) FALSO

D) FALSO: en todo momento hay una distancia recorrida en un tiempo en específico, es decir, una rapidez.

E) VERDADERO: el despazamiento sí depende de la distancia entre el punto de llegada y el punto de salida.

6 0

3 years ago

When you move from place to place, how do you know you moved ?

Nastasia [14]

If Your Somewhere Different .

7 0

3 years ago

When compounds form, what is one result for the atoms that bonded?

Anna35 [415]

One result for the atoms that bonded together when a compound forms is a stable arrangement of electrons.

3 0

3 years ago

Read 2 more answers

A cyclist on a training ride records the distance she travels away from home. The data only shows the first150 minutes of the ri

Varvara68 [4.7K]

Answer:

A) 58 km

B) 30 mins

Explanation:

In pic details

graph in pic

3 0

3 years ago

Para que ángulo el alcance es igual a la altura máxima en un lanzamiento de proyectil ideal sobre un plano horizontal. Translati

Gemiola [76]

Answer:

Explanation:

In projectile,

Maximum height = $\frac{u^{2}sin^{2} \theta }{2g}$ and range = $\frac{u^{2}sin2\theta }{g}$

u = velocity of the body

$\theta$ = angle of launch

g = acceleration due to gravity

If the range equals the maximum height in an ideal projectile launch on a horizontal plane, this means;

$\frac{u^{2}sin^{2} \theta }{2g} = \frac{u^{2}sin2\theta }{g}$

since $sin2\theta = 2sin\theta cos\theta$

$\frac{u^{2}sin^{2} \theta }{2g} = \frac{u^{2}2sin\theta cos\theta }{g}\\\frac{sin\theta}{2} =2cos\theta \\sin\theta = 4cos\theta\\\frac{sin\theta}{cos\theta} = 4\\tan\theta = 4\\\theta = tan^{-1} \\4\theta = 75.9^{0}$

The angle at which the range equals the maximum height in an ideal projectile launch on a horizontal plane is approximately 76°

8 0

4 years ago