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Blababa [14]
2 years ago
7

A ship travels with velocity given by 12, with current flowing in the direction given by 11 with respect to some co-ordinate axe

s.
What is the velocity of the ship in the direction of the current?
Physics
1 answer:
nataly862011 [7]2 years ago
7 0

Answer:

v_x = 11.78 m/s

Explanation:

Velocity of the ship is given as

v = 12 units

the direction of the velocity of the ship is making an angle of 11 degree with the current

so we will have two components of the velocity

1) along the direction of the current

2) perpendicular to the direction of the current

so here we know that the component of the ship velocity along the direction of the current is given as

v_x = v cos\theta

v_x = 12 cos11

v_x = 11.78 m/s

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A sphere is charged with electrons to -6 x 10^-6C. How many electrons make up this charge? The elemental charge is 1.6 x 10^-19
just olya [345]

Answer:

3.75*10^{-13}  electrons

Explanation:

The total charge Q is the sum of the charge of the N electrons contained in the sphere:

Q=N*q_{e}

q_{e}=-1.6*10^{-19}C    charge of a electron

We solve to find N:

N=\frac{Q}{q_{e}}=\frac{-6 x 10^{-6}}{-1.6 x 10^{-19}}=3.75*10^{-13}

7 0
3 years ago
What is the density of a piece of wood with a mass of 25 kg<br> and a volume of 0.0385 m³?
Orlov [11]

Answer:

649kg/m^3

Explanation:

Let p be the density of this particular object.

Formula for density:

p =  \frac{mass \: (in \: kg)}{volume \: (in \:  {m}^{3}) }

We can substitute the givenmass and volume to find density of the object.

p =  \frac{25kg}{0.0385 {m}^{3} }  \\  = 649kg \: per \:  {m}^{3}

Therefore the density of this object is 649kg/m^3.

7 0
1 year ago
A person observes a firework display for A safe distance of .750 km. Assuming that sound travels at 340 m/s in air what is the t
WINSTONCH [101]

Answer:

t = 2.2 s

Explanation:

Given that,

A person observes a firework display for A safe distance of 0.750 km.

d = 750 m

The speed of sound in air, v = 340 m/s

We need to find the between the person see and hear a firework explosion. let it is t. So, using the formula of speed.

v=\dfrac{d}{t}\\\\t=\dfrac{d}{v}\\\\t=\dfrac{750\ m}{340\ m/s}\\\\t=2.2\ s

So, the required time is 2.2 seconds.

3 0
2 years ago
An action force is 40 N to the right. The reaction force must be: A. 20 N left B. 40 N left C. 20 N right D. 40 N right
Sergeeva-Olga [200]

Answer:

The answer to your question is letter B.

Explanation:

To answer this question, we must remember the third law of motion of Newton that states that For every action, there is an equal and opposite reaction.

Then, if the action force is 40 N to the right, the reaction force must be 40 N to the left.

8 0
3 years ago
Which chart correctly describes the properties of electric and magnetic fields?
Serjik [45]
<span>Both electric and magnetic fields exert body forces, meaning they act from a distance. The like charges and poles in both repel; positive charge repels positive and the north pole repels the north pole. For both, the opposite poles/charges attract. Finally, only magnetic fields have poles, and there are two poles, namely the south and north, so they are dipolar. The diagram that represents all of this information correctly is the third.</span>
7 0
3 years ago
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