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Andre45 [30]
3 years ago
8

The actuon of a lever is affected by the?

Physics
1 answer:
mr Goodwill [35]3 years ago
4 0
The answer is pulley
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How much work would it take to push two protons very slowly from a separation of 2.00×10−10m (a typical atomic distance) to 3.00
laiz [17]

Answer:

Work= -7.68×10⁻¹⁴J

Explanation:

Given data

q₁=q₂=1.6×10⁻¹⁹C

r₁=2.00×10⁻¹⁰m

r₂=3.00×10⁻¹⁵m

To find

Work

Solution

The work done on the charge is equal to difference in potential energy

W=ΔU

Work=U_{1}-U_{2}\\ Work=-kq_{1}q_{2}[\frac{1}{r_{2}}-\frac{1}{r_{1}} ]\\Work=(-9*10^{9})*(1.6*10^{-19} )^{2}[\frac{1}{3.0*10^{-15} }-\frac{1}{2*10^{-10} } ]\\  Work=-7.68*10^{-14}J

4 0
4 years ago
Heather and Matthew walk with an average velocity of 0.98 m/s eastward. If it takes them 34 min to walk to the store, what is th
TEA [102]

Answer:

D= 1999.2 m

Explanation:

Given that

Average velocity ,v= 0.98 m/s

time ,t= 34 min

We know that

1 min  = 60 s

That is why

t= 34 x 60 =2040 s

We know that

Displacement = Average velocity x time

D= v t

Now by putting the values in the above equation

D= 0.98 x 2040 m

D= 1999.2 m (eastward)

The direction of the displacement will be towards eastward.

That is why the displacement will be 1999.2 m or we can say that 1.9992 km.

3 0
3 years ago
An object is 1.0 cm tall and its erect image is 5.0 cm tall. what is the exact magnification?
ikadub [295]
The exact magnification of the objects is calculated by dividing the cinema. We calculate it by diving the erect image size by the object size. From the given above, we find the exact magnification by dividing 5.0 cm by 1.0 cm. Thus, the answer would be 5. 
7 0
3 years ago
The pupil of your eye
Sav [38]

Answer:

What is the question?

Explanation:

If you tell me the question I can help.

3 0
3 years ago
What are the horizontal and vertical velocities of a stunt bike that leaves a ramp at 100 km/hr and at an angle of 35 degrees?
Alex787 [66]

Horizontal velocity: 81.9 km/h

Vertical velocity: 57.4 km/h

Explanation:

We can solve this problem by resolving the velocity vector into its component along the horizontal and vertical direction.

The horizontal velocity of the stunt bike is given by:

v_x = v cos \theta

where

v = 100 km/h is the magnitude of the velocity

\theta=35^{\circ} is the angle of projection

Substituting, we find

v_x = (100)(cos 35^{\circ})=81.9 km/h

The vertical velocity instead is given by

v_y = v sin \theta

where

v=100 km/h

\theta=35^{\circ}

Substituting,

v_y = (100)(sin 35^{\circ})=57.4 km/h

Learn more about vector components:

brainly.com/question/2678571

#LearnwithBrainly

4 0
3 years ago
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