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Tems11 [23]
3 years ago
14

What conclusion did you reach? were the components of the dyes similar or different? justify your answer using your empirical ev

idence?
Mathematics
1 answer:
Doss [256]3 years ago
4 0
The components of the dyes were definitely different. Regardless of small similarity, they all proved to be independent from one another. While coloring remained the same, the amount in each component was different (and was evident when the water traveled up the paper strip and dissolved into its various pigments and coloring agents). Smaller molecules traveled farther than larger ones, however it is apparent by our varying Rf values that the difference even between similar colors highlights the change amongst the dyes.
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At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

7 0
4 years ago
What is m∠VWX? 75° 69° 119° 25°
Bogdan [553]

Answer:

Step-by-step explanation:

Sum of interior angles of a triangle = Exterior angle

m∠VWX + m∠WVX = Exterior angle = 155°

m∠VWX + 86° = 155°

m∠VWX = 69°

6 0
3 years ago
Read 2 more answers
Which of the following could be a measurement on a scale drawing that has a scale of 2:5? 2 in.:5 ft
12345 [234]
It's the1st: 4 cm/10 cm because:
4/10 = 2/5 .  and because they have the SAME UNIT (cm)
6 0
4 years ago
How would i solve the math problem of x&gt;3
Verizon [17]
I think any number mor than 3
6 0
3 years ago
What percent of 140 is equal to 7% of 500​
blagie [28]

Answer:

49%

Step-by-step explanation:

7 percent of 500=35%

4 0
3 years ago
Read 2 more answers
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