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3 years ago

What is the largest-aperture Earth-based telescope currently in use at visible wavelengths?

Physics

1 answer:

Svetlanka [38]3 years ago

3 0

Answer:

Gran Telescopio Canarias

Explanation:

There are numerous giant telescopes all over the world which give us amazingly details data of the Universe. These work in various wavelengths. Talking about the telescopes which operates in visible wavelengths, the largest operational telescope will be Gran Telescopio Canarias. This telescope has an aperture of 10.4m. It is situated in Canary Island, Spain.

In future larger telescopes such as Thirty Meter Telescope and EELT will will make it look like a small telescope.

You might be interested in

What is the magnitude (in N/C) and direction of an electric field that exerts a 4.00 x 10^−5 N upward force on a −2.00 µC charge

emmasim [6.3K]

Answer:

The magnitude of electric field is $1.25\times10^{14}\ N/C$ in downward.

Explanation:

Given that,

Force $F= 4.00\times10^{-5}\ N$

Charge q= -2.00 μC

We know that,

Charge is negative, then the electric field in the opposite direction of the exerted force.

We need to calculate the magnitude of electric field

Using formula of electric force

$F = qE$

$E = \dfrac{F}{q}$

$E=\dfrac{4.00\times10^{-5}}{-2.00\times1.6\times10^{-19}}$

$E=-1.25\times10^{14}\ N/C$

Negative sign shows the opposite direction of electric force.

Hence, The magnitude of electric field is $1.25\times10^{14}\ N/C$ in downward.

8 0

4 years ago

What is quantum programing

Komok [63]

Answer: Quantum programming is the process of assembling sequences of instructions, called quantum programs, that are capable of running on a quantum computer. Quantum programming languages help express quantum algorithms using high-level constructs.

Explanation:

7 0

4 years ago

Suppose there is a bright fringe at P Would this bright fringe move closer to O, move further away, or be unchanged, t 1.5 marks

fiasKO [112]

Answer:

Explanation:

The distance of a fringe from centre is proportional to wavelength of light

and inversely proportional to separation of slits. The expression for distance x is given by

x = nλ D / d

where λ is wave length , D is screen distance and d is slit separation.

So first option only is correct because

1 ) the wavelength of blue light is less than that of red

2) Intensity of light does not affect distance of fringe from the centre.

Diffraction symbolises bending of light around sharp edges like slits or boundaries of opaque objects etc.Due to this reason , we do not observe sharp boundary of shadow of an object. Instead around the boundary of shadow, we observe bands of bright and dark color which are also called fringes.

The phenomena of diffraction is explained by wave theory of light.

3 0

3 years ago

A gold wire has a cross-sectional area of 1.0 cm^2 and a resistivity of 2.8 × 10^-8 Ω ∙ m at 20°C. How long would it have to be

Karo-lina-s [1.5K]

Answer:

Length, l = 3.57 meters

Explanation:

It is given that,

Area of cross-section of gold wire, $A=1\ cm^2=0.0001\ m^2$

Resistivity of gold wire, $\rho=2.8\times 10^{-8}\ \Omega-m$

Resistance, R = 0.001 ohms

Resistance in terms of length and area is given by :

$R=\rho \dfrac{l}{A}$

$l=\dfrac{RA}{\rho}$

$l=\dfrac{0.001\times 0.0001}{2.8\times 10^{-8}}$

l = 3.57 meters

So, the length of the wire is 3.57 meters. Hence, this is the required solution.

4 0

3 years ago

A bucket of water of mass 14.7 is suspended by a rope wrapped around a windlass, that is a solid cylinder with diameter 0.280m w

Snowcat [4.5K]

Answer:

Explanation:

Tension T in the rope will create torque in solid cylinder ( axle ). If α be angular acceleration

T R = 1/2 M R²α ( M is mass and R is radius of cylinder )

= 1/2 M R² x a / R ( a is linear acceleration )

T = Ma / 2

For downward motion of the bucket

mg - T = m a ( m is mass and a is linear acceleration of bucket downwards )

mg - Ma / 2 = ma

a = mg / ( M /2 + m )

Substituting the values

a = 14.7 x 9.8 / ( 5.8+ 14.7 )

= 7 m / s²

A )

T = Ma / 2

= 5.8 x 7

= 40.6 N

B ) v² = u² + 2 a h

= 2 x 7 x 10.3

v = 12 m /s

C )

v = u + a t

12 = 0 + 7 t

t = 1.7 s

6 0

3 years ago