1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DaniilM [7]
3 years ago
15

What is the largest-aperture Earth-based telescope currently in use at visible wavelengths?

Physics
1 answer:
Svetlanka [38]3 years ago
3 0

Answer:

Gran Telescopio Canarias

Explanation:

There are numerous giant telescopes all over the world which give us amazingly details data of the Universe. These work in various wavelengths. Talking about the telescopes which operates in visible wavelengths, the largest operational telescope will be Gran Telescopio Canarias.  This telescope has an aperture of 10.4m. It is situated in Canary Island, Spain.

In future larger telescopes such as Thirty Meter Telescope and EELT will will make it look like a small telescope.

You might be interested in
Two pulses move in opposite directions on a string and are identical in shape except that one has positive displacements of the
Leni [432]

(c) When the two pulses completely overlap on the string forms a straight line.

A single disturbance that travels via a transmission medium is referred to as a pulse. This medium might be formed of stuff or a vacuum, and it might be endlessly large or finite in size.

Consider two pulses that are identical in shape and proceed in opposite directions along a string, with the exception that one has positive displacements of the string's elements while the other has negative displacements.

On the string, the two pulses blend together completely.

The pulses completely balance one another out in terms of removing string elements from equilibrium, yet the string still moves. Shortly after the string is once again shifted, the pulses will have passed each other.

The correct option is (c)

Learn more about pulse here:

brainly.com/question/14885673

#SPJ4

6 0
1 year ago
Efficiency is given by A. actual output divided by effective capacity. B. design capacity divided by utilization. C. effective c
jok3333 [9.3K]

Answer:

A

Explanation:

Actual output divided by the effective capacity. It is the ratio of output to effectiveness

5 0
3 years ago
Read 2 more answers
What is the term for substances that have several unpaired electrons and are strongly magnetic
Murljashka [212]

Answer:

Scientific definitions for ferromagnetic

The property of being strongly attracted to either pole of a magnet. Ferromagnetic materials, such as iron, contain unpaired electrons, each with a small magnetic field of its own, that align readily with each other in response to an external magnetic field.

Explanation:

8 0
3 years ago
A parallel-plate capacitor stores charge Q. The capacitor is then disconnected from its voltage source, and the space between th
Stells [14]

Answer:

The relationship between the initial stored energy PE_{i} and the stored energy after the dielectric is inserted PE_{f} is:

c) PE_{f} =0.5\ PE_{i}

Explanation:

A parallel plate capacitor with C_{o} that is connected to a voltage source V_{o} holds a charge of Q_{o} =C_{o} V_{o}. Then we disconnect the voltage source and keep the charge Q_{o} constant . If we insert a dielectric of \kappa=2 between the plates while we keep the charge constant, we found that the potential decreases as:

                                                     V=\frac{V_{o}}{\kappa}

The capacitance is modified as:

                                              C=\frac{Q}{V} =\kappa\frac{Q_{o}}{V_{o}}=\kappa\ C_{o}

The stored energy without the dielectric is

                                               PE_{i}=\frac{1}{2}\frac{Q_{o}^{2}}{C_{o}}=\frac{1}{2}C_{o}V_{o}^{2}

The stored energy after the dielectric is inserted is:

                                               PE_{f}=\frac{1}{2}\frac{Q^{2}}{C}=\frac{1}{2}CV^{2}

If we replace in the above equation the values of V and C we get that

                                         PE_{f}=\frac{1}{2}\kappa\ C_{o}(\frac{V_{o}}{\kappa})^{2}=\frac{1}{\kappa}(\frac{1}{2}C_{o}V_{o}^{2})

                                                   PE_{f} =\frac{PE_{i}}{\kappa}

Finally

                                                  PE_{f} =0.5\ PE_{i}

                                               

                                     

5 0
3 years ago
What are the characteristics of low energy waves?
Leokris [45]
I think the correct answer from the choices presented above is the first option. The characteristics of low energy waves are <span>long wavelengths and low frequencies. Energy is established to be indirectly proportional to wavelengths and frequencies.</span>
8 0
3 years ago
Read 2 more answers
Other questions:
  • A positive charge on an object is caused by:
    15·2 answers
  • Below are two of the seven original Axioms of URT.
    8·1 answer
  • 4. You make the following measurements of an object: 42 kg and 22 m3. What would the object’s density be?
    13·1 answer
  • Josh rolled a bowling ball down a lane in 2.5 seconds. The ball travelled at a constant acceleration of 1.8 m/s/s down the lane
    6·1 answer
  • Technician A says that one of advantages of a clutch brake is its ability to bring a vehicle to a halt at low speeds. Technician
    12·1 answer
  • What moon phase occurs 3-4 days after a waning gibbous?
    11·1 answer
  • Who was the first president of America​
    5·2 answers
  • PLEASE HELP, PLS HELP...
    15·1 answer
  • What is (a) the x component and (b) the y component of the net electric field at the square's center
    7·1 answer
  • Define specific vision??​
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!