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uysha [10]
3 years ago
8

Luigi is an urban planner. As an independent contractor, he charges a $140 fee plus $25 per hour for each contract with the city

.
Write a function to represent this scenario where y represents the total amount her charges for a project and x represents the number hours worked on a project. what is the amount earned after 10 hours of work?
Mathematics
2 answers:
IrinaK [193]3 years ago
5 0
25x+140=y. 25(10)+140=390.
Contact [7]3 years ago
4 0

Answer:  The function representing the scenario is y=140+25x and the amount earned after 10 hours is $ 390.

Step-by-step explanation:  Given that Luigi is an independent contractor who charges a $140 fee plus $25 per hour for each contract with the city.

We are to write a function representing the scenario where y represents the total amount her charges for a project and x represents the number hours worked on a project.

Also, to find the amount earned after 10 hours of work.

The number of hours Luigi work on a project is represented by x.

So, the amount charged by Luigi for a project is given by

140+25x.

Since y represents the total amount charged by Luigi on a project, therefore we must have

y=140+25x.

Now, if Kuigi work for 10 hours, then we have

x = 10.

Therefore,

y=140+25x=140+25\times 10=140+250=390.

Thus, the function representing the scenario is y=140+25x and the amount earned after 10 hours is $ 390.

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Answer:

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The point-slope form of the equation of a line will give you the desired linear function:

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You are give point (x, f(x)) = (-11, 5) = (h, k), and you are given slope m = -2/3. Putting these values into the function form gives ...

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A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard
Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

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Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

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From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

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Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

8 0
3 years ago
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