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LUCKY_DIMON [66]
3 years ago
11

According to the law of conservation of charge in alpha decay the total number of protons on one side of the equation equals the

total number of protons on the other side of the equation true or false
Physics
1 answer:
Artyom0805 [142]3 years ago
3 0

Answer:

True

Explanation:

For any equation to be balanced, be it elemental equation or radioactive decay equation, the number of atoms on the left must balance the number of atoms of the right. The same is true for alpha decay as the number of protons on the left side must equal the number of protons on the right side?

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(a) What is the potential between two points situated 10 cm and 20 cm from a 3.0-μC point charge? (b) To what location should th
julia-pushkina [17]

Answer:

(a) 135 kV

(b) The charge chould be moved to infinity

Explanation:

(a)

The potential at a distance of <em>r</em> from a point charge, <em>Q</em>, is given by

V = -\dfrac{kQ}{r}

where k = 9\times 10^9 \text{ F/m}

Difference in potential between the points is

kQ\left[-\dfrac{1}{0.2\text{ m}} -\left( -\dfrac{1}{0.1\text{ m}}\right)\right] = \dfrac{kQ}{0.2\text{ m}} = \dfrac{9\times10^9\text{ F/m}\times3\times10^{-6}\text{ C}}{0.2\text{ m}}

PD = 135\times 10^3\text{ V} = 135\text{ kV}

(b)

If this potential difference is increased by a factor of 2, then the new pd = 135 kV × 2 = 270 kV. Let the distance of the new location be <em>x</em>.

270\times10^3 = kQ\left[-\dfrac{1}{x}-\left(-\dfrac{1}{0.1\text{ m}}\right)\right]

10 - \dfrac{1}{x} = \dfrac{270000}{9\times10^9\times3\times10^{-6}} = 10

\dfrac{1}{x} = 0

x = \infty

The charge chould be moved to infinity

7 0
3 years ago
A 1500 kg car skids to a halt on a wet road where μk = 0.47. You may want to review (Pages 141 - 145) . Part A How fast was the
shusha [124]

The car travels at a speed of 25m/s.

<u>Explanation:</u>

Given-

Mass, m = 1500kg

Coefficient of friction, μk = 0.47

Distance, x = 68m

Speed, s = ?

We know,

Force, F = ma

and

F = μ X m X g

Therefore,

μ * m * g = m * a

μ * g = a

Let, g = 9.8m/s²

So,

a = 0.47 * 9.8 m/s^2

a = 4.606m/s^2

We know,

v^2 - u^2 = 2as

where, v is the final velocity

           u is the initial velocity

           a is the acceleration

           s is the distance

If the car comes to rest, the final velocity, v becomes 0.

So,

u^2 = 2 * 4.606 * 68\\\\u^2 = 626.416m/s\\\\u = 25m/s

The car travels at a speed of 25m/s.

6 0
3 years ago
What is the work-energy theorem equation?
grin007 [14]

Answer:

W = Fd = KE =1/2mv²

Explanation:

not sure if that's what your looking for but i'm pretty sure this is it.

7 0
3 years ago
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a train traveling at 30m/s comes to a complete stop in 20 sec.how far did the train go during the deceleration
elixir [45]

Answer:

600m

Explanation:

v=30m/s

t=20s

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20×30=600m

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