Question

An 80kg student running at 3.50m/s grabs a rope that is hanging vertically. How high will the student swing?

Answer 1

Answer:

The student will swing to a height of 61.25 cm.

Explanation:

Given that,

Mass of the student, m = 80 kg

Speed of student, v = 3.5 m/s

The student running at this speed grabs a rope that is hanging vertically. In the whole process, the energy of the system remains conserved. So, using conservation of energy to find the height reached by the student. So,

$\dfrac{1}{2}mv^2=mgh$

h is height reached by the student

$h=\dfrac{v^2}{2g}\\\\h=\dfrac{(3.5)^2}{2\times 10}\\\\h=0.6125\ m\\\\h=61.25\ cm$

So, the student will swing to a height of 61.25 cm.