A 513 g ball strikes a wall at 12.1 m/s and
1 answer:
The average force on the ball is 287.3 N.
Explanation:
The impulse exerted on an object, which is equal to the product between the force exerted and the duration of the collision, is equal to the change in momentum of the object.
If we apply this to the ball, we can write:
where
F is the force exerted on the ball
is the duration of the collision
m = 513 g = 0.513 kg is the mass of the ball
u = 12.1 m/s is the initial velocity of the ball
v = -13.1 m/s is the final velocity (negative since the ball rebounds in the opposite direction)
And solving for F, we find:
So, the magnitude of the average force is 287.3 N.
Learn more about impulse and change in momentum:
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Answer:
E.) conservation of angular momentum
Explanation:
The angular momentum is defined as:
x
where is the radius of the star,
is the mass and
the angular velocity.
and angular momentum is an amount that is conserved, so the angular momentum before the star is compressed must be equal to the angular momentum after the star was compressed:
x
x
the second radius is smaller than the first radius, since the star shrinked, the second angular velocity must be greater that the first.
In other words, the angular velicity increases as the star shrinks because of the conservation of angular momentum.