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Kisachek [45]
4 years ago
15

Explain why the liquid with the median density floats where it does

Physics
1 answer:
emmainna [20.7K]4 years ago
5 0
Hey wats there answerssssssssssssss need it nowwwwwwww ASAP !!!!!!!
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A rocket initially at rest accelerates at a rate of 99.0 meters/second2. Calculate the distance covered by the rocket if it atta
Jobisdone [24]

Answer: The correct answer is option b.

Explanation: We are given that the rocket is at rest initially final velocity is 445m/s.

The acceleration of the rocket is 99.0m/s^2

To calculate the distance of rocket, we use third equation of motion, which is:

v^2-u^2=2as

where, v = final velocity = 445m/s

u = initial velocity = 0m/s

a = acceleration = 99m/s^2

s = distance = ? m

Putting values in above equation, we get:

(445)^2-(0)^2=2(99)s\\\\s=1\times 10^3meters

3 0
3 years ago
A fan uses 7A when connected to a 110V line. If electric power costs 10 cents per kilowatt-hour in this location, what is the co
Anna007 [38]
Power = current x voltage

So the power is 7 x 110 = 770 W = 0.77kW

0.77 x 13 = 10.01 kWh

10.01 x 10 cents = 100.1 cents (is this 1 dollar? Idk I use a different currency)
6 0
4 years ago
Why don't atoms get too close?
Kamila [148]

Answer:

<h3>This tends not to happen, because atoms are composed of charged particles that interact at a distance. ... Since the electrons are around the outside of the atom, those are the things that first interact, and as they have the same charge, they repel one another.</h3>

A. The electrons from atom repel each other

5 0
3 years ago
Read 2 more answers
The table below shows the height of some horse fossils.
choli [55]

Answer:

Y W Z X, B

Explanation:

It wants you to figure out the correct order starting from oldest to newest.

7 0
3 years ago
Read 2 more answers
Suppose that 2 J of work is needed to stretch a spring from its natural length of 34 cm to a length of 46 cm. (a) How much work
dlinn [17]

Answer:

0.83 J of work

Explanation:

2 J of work is required to stretch a spring from 34cm to 46cm

So that is 12cm stretched with 2 J of work

We can make that 6cm for 1 J of work

So, we need the find the work for stretching 36cm to 41cm

Which is 5cm

So, What is the work required to stretch 5cm?

1 J of work for 6cm

x work for 5cm

So, by proportion method

1 : 6 :: x : 5

6 * x = 1 * 5

6x = 5

x = 5/6

= 0.83

So to stretch 36cm to 41cm we need 0.83 J of work

4 0
3 years ago
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