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PilotLPTM [1.2K]
3 years ago
6

Which statement is correct

Chemistry
2 answers:
alisha [4.7K]3 years ago
6 0
The answer to your question is A.
elixir [45]3 years ago
3 0
A is the correct answer
You might be interested in
What mass of iron is formed when 10 grams of carbon react with 80 grams of iron iii oxide?
yKpoI14uk [10]

Answer:

55.85 grams of Fe is formed.

Explanation:

Identify the reaction:

2Fe₂O₃  +  3C  →  4Fe  +  3CO₂

Identify the limiting reactant, previously determine the mol of each reactant

(mass / molar mass)

10 g / 12 g/m = 0.83 moles C

80 g / 159.7 g /m = 0.500 moles Fe₂O₃

2 moles of oxide need 3 moles of C, to react

0.5 moles of oxide, will need ( 0.5  . 3)/ 2 = 0.751 mol

I have 0.83 moles of C, so C is the excess.

The limiting is the oxide.

3 mol of C need 2 mol of oxide to react

0.83 mol of C, will need (0.83  . 2)/ 3 = 0.553 mol of oxide, and I only have 0.5 (That's why Fe₂O₃ is the limiting)

Ratio is 2:4 (double)

If I have 0.5 moles of oxide, I will produce the double, in the reaction.

1 mol of Fe, will be produce so its mass is 55.85 g

5 0
3 years ago
A carpet sells for $28.99 a square yard. What is the price of the carpet per square meter?
9966 [12]

It is given that the price of the carpet is $ 28.99 per square yard

Step 1: Convert square yard to square meter

1 square yard = 0.836 square meter

Step 2: Calculate the cost/square meter

Now based on the relation in step (1) we can write

0.836 square meter of carpet costs $ 28.99

Therefore the cost of 1 square meter of the carpet would be

= $ 28.99 * 1 sq meter/0.836 sq meter

= $ 34.68

7 0
3 years ago
Read 2 more answers
hat is the pH of a solution with a hydroxide ion concentration of 10–6M? A. pH = 12 B. pH = 8 C. pH = 6 D. pH = 7
WARRIOR [948]
C=10⁻⁶ mol/L

pH=14-pOH

pOH=-lg[OH⁻]

pH=14+lg10⁻⁶=14-6=8

B. pH = 8

8 0
3 years ago
A gas has a pressure of 5.7 atm at 100.0°C. What is its pressure at20.0°C (Assume volume is unchanged)
son4ous [18]

Answer:

\large \boxed{\text{4.5 atm}}

Explanation:

The volume and amount of gas are constant, so we can use Gay-Lussac’s Law:

At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}

Data:

p₁ =5.7 atm; T₁ = 100.0 °C

p₂ = ?;          T₂ =  20.0 °C

Calculations:

1. Convert the temperatures to kelvins

T₁ = (100.0 + 273.15) K = 373.15

T₂ =  (20.0 + 273.15) K = 293.15

2. Calculate the new pressure

\begin{array}{rcl}\dfrac{5.7}{373.15} & = & \dfrac{p_{2}}{293.15}\\\\0.0153 & = & \dfrac{p_{2}}{293.15}\\\\0.0153\times 293.15 &=&p_{2}\\p_{2} & = & \textbf{4.5 atm}\end{array}\\\text{The new pressure will be $\large \boxed{\textbf{4.5 atm}}$}

6 0
3 years ago
Select multiple choices.<br><br> Thank you
AnnZ [28]
D, systems of writing
4 0
3 years ago
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