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PilotLPTM [1.2K]
3 years ago
6

Which statement is correct

Chemistry
2 answers:
alisha [4.7K]3 years ago
6 0
The answer to your question is A.
elixir [45]3 years ago
3 0
A is the correct answer
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Which pair of elements do you expect to be most similar in their chemical properties?which pair of elements do you expect to be
AVprozaik [17]
Elements with the same properties would be in the same group (Up and down row). Look at a periodic table and see which of the elements are in the same group. That will be your answer.<span />
7 0
3 years ago
Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Ca2+, V5+, Br-
Jet001 [13]

Answer:

CaS, CaBr₂, VBr₅, and V₂S₅.

Explanation:

  • The ionic compound should be neutral; the overall charge of it is equal to zero.
  • Binary ionic compound is composed of two different ions.

<u>Ca²⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds.</u>

  • CaS can be formed via combining Ca²⁺ with S²⁻ to form the neutral binary ionic compound CaS.
  • CaBr₂ can be formed via combining 1 mole of Ca²⁺ with 2 moles of Br⁻ to form the neutral binary ionic compound CaBr₂.

<u>V⁵⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds.</u>

  • V₂S₅ can be formed via combining 2 moles of V⁵⁺ with 5 moles of S²⁻ to form the neutral binary ionic compound V₂S₅.
  • VBr₅ can be formed via combining 1 mole of V⁵⁺ with 5 moles of Br⁻ to form the neutral binary ionic compound VBr₅.

<em>So, the empirical formula of four binary ionic compounds that could be formed is: CaS, CaBr₂, VBr₅, and V₂S₅.</em>

<em></em>

5 0
3 years ago
HElp i am stuck and i am not sure
alexandr1967 [171]

Answer:

B

Explanation:

hope this helps...

7 0
2 years ago
The half-life for the radioactive decay of C-14C-14 is 5730 years. You may want to reference (Pages 598 - 605) Section 14.5 whil
KIM [24]

<u>Answer:</u> The sample of Carbon-14 isotope will take 2377.9 years to decay it to 25 %

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life of the reaction = 5730 years

Putting values in above equation, we get:

k=\frac{0.693}{5730yrs}=1.21\times 10^{-4}yrs^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant  = 1.21\times 10^{-4}yr^{-1}

t = time taken for decay process = ? yr

[A_o] = initial amount of the sample = 100 grams

[A] = amount left after decay process =  (100 - 25) = 75 grams

Putting values in above equation, we get:

1.21\times 10^{-4}=\frac{2.303}{t}\log\frac{100}{75}\\\\t=2377.9yrs

Hence, the sample of Carbon-14 isotope will take 2377.9 years to decay it to 25 %

8 0
3 years ago
How to find weight with volume and density ​
stira [4]

Answer:

Explanation:

Look up the density of the material the object is made of in kg/m³.

Measure the volume of the object in m³.

Multiply the density by the volume.

You will then have the mass of the object in kg.

5 0
3 years ago
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