The wrong answers for sure are B and D, I assume the answer is C
Answer:
Average atomic mass = 17.5 amu.
Explanation:
Given data:
X-17 isotope = atomic mass17.2 amu, abundance:78.99%
X-18isotope = atomic mass 18.1 amu, abundance 10.00%
X-19isotope = atomic mass:19.1 amu, abundance: 11.01%
Average atomic mass of X = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass) / 100
Average atomic mass = (78.99×17.2)+(10.00×18.1) +(11.01+ 19.1) /100
Average atomic mass = 1358.628 + 181 +210.291 / 100
Average atomic mass = 1749.919 / 100
Average atomic mass = 17.5 amu.
Answer
2-methyl-2-pentene
Explanation:
1. Identify the group that takes precedence in this case alkene hence this molecule is an alkene with a methyl group side chain.
2.Find the longest carbon chain where the functional group(alkene group in this case) has the lowest Carbon number
3.What are the side groups? One side group can be seen at carbon 2 this group is methyl
4. Naming, number separated by "," and number from letters by "-" so the compound should be
2-methyl-2-pentene
