Answer:
The circuit impedance is 3.84 phase 38.65º and the voltage across the capacitor is 0.13 phase -128.65º V.
Explanation:
Since the voltage given to us was Vs = 5*cos(5t) V and it is the form of V = Vmax*cos(omega*t) V we can extract the frequency omega, wich is w = 5 rad/s.
In the circuit we have a capacitor and a inductor. The capacitor impedance is negative and it is inversely proportional to the frequency, while the inductor impedance is positive and directly proportional to the frequency. So we have:
Z = R + jw*L - j/(wC)
Z = 3 + j*5*0.5 - j/(5*2)
Z = 3 + j*2.5 - j*0.1 = 3 + j*2.4 Ohm = 3.84 phase 38.65º Ohm
To find out the voltage across the capacitor we can use a voltage divider equation that is:
Vcapacitor = [Zcapacitor/(R + Zinductor + Zcapacitor)] * Vsource
Vcapacitor = [(-j0.1)/(3 + j2.4)]*Vsource
Vcapacitor = [(0.1 phase -90º)/(3.84 phase 38.65º)]*5 phase 0º
Vcapacitor = [0.026 phase -128.65º]* 5 phase 0º
Vcapacitor = 0.13 phase -128.65º V
Answer:
Z = 3 + 0.23t
The water level is rising
Explanation:
Please see attachment for the equation
I’m in 6th grade I’m sorry
Answer:
39⁰
Explanation:
We have cohesion c = 25kpa
Then the normal stress = 39kpa
Shear stress = 56kpa
This question is asking us to find the angle of internal friction
Shear stress at the time of failure = cohesion C + normal stresstanΦ
56 = 25 + 39tanΦ
Φ = angle if refractive index
Φ = 38.48⁰
This is approximately 39⁰
Therefore in answer to this question, the angle of internal friction for the soil is nearly 39⁰
S
Answer:
I hope following attachment will help you a lot!
Explanation: