**Answer:**

**Explanation:**

The capacitive reactance of the capacitor is determined by

When

and

(The capacitive reactance will be reduced into 1/2 times of the previous capacitive reactance)

Answer:

a) 1725.93 rpm

b) α = 3.012 rad/s²

Explanation:

The centrifugal acceleration is given by

a = v²/r

a = 1000 g = 1000 × 9.8 = 9800 m/s²

v = velocity = ?

r = radius of motion = 300 mm = 0.3 m

9800 = v²/0.3

v² = 2940

v = 54.22 m/s

v = rw

w = angular speed

54.22 = 0.3 × w

w = 54.22/0.3 = 180.74 rad/s

w = 2πf

f = frequency in rev/s

180.74 = 2πf

f = 28.77 rev/s

f = 1725.93 rpm

b) Using the equations of motion,

Since the centrifuge starts from rest,

w₀ = 0 rad/s

w = 180.74 rad/s (equivalent to the f = 1725.93 rpm)

t = 1 min = 60 s

α = ?

w = w₀ + αt

180.74 = 0 + 60α

α = 3.012 rad/s²

**Answer:**

(b) BC → A

**Explanation:**

For given instance of S, certain dependencies (that is to say, A → B and B → C) can be said that they are not violated by this instance of S.

It can be said that an FD holds with respect to a relationship is to make a claim about all appropriate instances of S.

BC → A does not hold over S. To confirm, let's look at the tuples (1, 2, 3) and (4, 2, 3).

Hence, the answer is (b) BC → A.

**Answer:**

(a) 16.27 Vpk

(b) 48.7%

**Explanation:**

The **transformer** is assumed to be an **ideal** 10:1 voltage divider with no internal impedance. The **diode** is assumed to be modeled in the forward direction by a perfect **0.7 V voltage** drop with no internal impedance. That means the frequency of the supply voltage is irrelevant.

__

<h3>(a)</h3>

The **peak voltage** will be 0.7 V less than the transformer secondary peak voltage:

((120 V)√2)/10 -0.7 V ≈** 16.27 V**

__

<h3>(b)</h3>

The fraction of the amplitude for which the diode is non-conducting is ...

0.7/(12√2) ≈ 0.041248

The period of conduction is symmetrical about the peak of the waveform, so it is convenient to use the arccos function to find the (half) conduction angle:

arccos(0.041248) ≈ 87.64°

As a fraction of half the cycle, this is ...

**conduction fraction** ≈ 87.64°/180° ≈** 48.7%**