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3 years ago

7

The lift on a spinning circular cylinder in a freestream with a velocity of 30 m/s and at standard sea level conditions is 6 N/m

of span. Calculate the circulation around the cylinder

1 answer:

Evgesh-ka [11]3 years ago

5 0

Answer:

The circulation around the cylinder is 0.163 $\frac{m^{2} }{s}$

Explanation:

Given :

Velocity of spinning cylinder $v = 30$ $\frac{m}{s}$

Sea level density $\rho = 1.23$ $\frac{kg}{m^{3} }$

Sea level span $L = 6$ $\frac{N}{m}$

Lift per unit circulation is given by,

$L = \rho v c$

Where $c =$ circulation around cylinder

$c = \frac{L}{\rho v}$

$c = \frac{6}{1.23 \times 30}$

$c = 0.163$ $\frac{m^{2} }{s}$

Therefore, the circulation around the cylinder is 0.163 $\frac{m^{2} }{s}$

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Answer:

final temperature is 424.8 K

so correct option is e 424.8 K

Explanation:

given data

pressure p1 = 1 bar

pressure p2 = 5 bar

index k = 1.3

temperature t1 = 20°C = 293 k

to find out

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we have given compression is reversible and has an index k

so we can say temperature is

$\frac{t2}{t1}= [\frac{p2}{p1}]^{\frac{k-1}{k} }$ ...........1

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3 years ago

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Answer:

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b) Using the coenergy the mechanical force is -226.2 N

Explanation:

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$\frac{\delta w_{f} }{\delta g} =\frac{g^{2}\lambda ^{3} }{3*1.2^{2} }$

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Answer:

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3 years ago

Four kilograms of carbon monoxide (CO) is contained in a rigid tank with a volume of 1 m3. The tank is fitted with a paddle whee

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Answer:

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c) 514 kJ

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<u>Given </u>

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-The volume of the tank V_tank = 1 m^3

-The added energy E = 14 W

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