The vibration produced days or even years before an earthquake

You and a friend each hold a lump of wet clay. Each lump has a mass of 30 grams. You each toss your lump of clay into the air, w

Vesna [10]

Answer:

$\ \text{m/s}$

Explanation:

$u_1$ = Velocity of one lump = $3x+3y-3z$

$u_2$ = Velocity of the other lump = $-4x+0y-4z$

m = Mass of each lump = $30\ \text{g}$

The collision is perfectly inelastic as the lumps stick to each other so we have the relation

$mu_1+mu_2=(m+m)v\\\Rightarrow m(u_1+u_2)=2mv\\\Rightarrow v=\dfrac{u_1+u_2}{2}\\\Rightarrow v=\dfrac{3x+3y-3z-4x+0y-4z}{2}\\\Rightarrow v=-0.5x+1.5y-3.5z=\ \text{m/s}$

The velocity of the stuck-together lump just after the collision is $\ \text{m/s}$ .

4 0

2 years ago

Which of the following statements is true?

Alborosie

My guess is A. I'm not 100% positive but i'm pretty sure.

8 0

2 years ago

If 1 gallon of a liquid weighs 4 pounds how much would one ounce weight (keep in mind that liquid ounces are different than weig

Bas_tet [7]

Answer:

64 ounces

Explanation:

Pound is the unit of mass in the imperial system of units. It is used in the United States. Its calibration is done with the SI unit of mass which is kilogram. 1 lb = 0.45359237 kg

1 gallon = 4 pounds

1 pound = 16 ounces weight

So,

4 pounds = 16 × 4 = 64 ounces weight

So, 1 gallon is equal to 64 ounces weight.

1 gallon = 128 fluid ounces.

3 0

3 years ago

A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axi

Hitman42 [59]

Answer:

the balls reached a height of 4.9985 m

Explanation:

Given the data in the question;

mass one m = 3.8 kg

mass two M = 2.1 kg

Initial velocities

u = 22 m/s

U = { moving downward} = 12 m/s

Now, using the law conservation of linear moment;

mu + MU = v( m + M )

we solve for "v" which is the velocity of the ball s after collision;

v = (mu + MU) / ( m + M )

so we substitute our given values into the equation

v = ( ( 3.8 × 22 ) + ( 2.1 × -12) ) / ( 3.8 + 2.1 )

v = ( 83.6 - 25.2 ) / 5.9

v = 58.4 / 5.9

v = 9.898 m/s

Now, we determine required height using the following relation;

v"² - v² = 2gh

where v" is the velocity at the top which is 0 m/s and g = -9.8 m/s²

0 - v² = 2gh

v² = -2gh

so we substitute

( 9.898 )² = -2 × -9.8 × h

97.97 = 19.6 × h

h = 97.97 / 19.6

h = 4.9985 m

Therefore, the balls reached a height of 4.9985 m

8 0

3 years ago

When a wave strikes a new medium, three things can happen: reflection, transmission, and absorption. Consider an echo. Do you th

kolbaska11 [484]

Answer:

YES

Explanation:

An echo may be defined as a sound which is repeated because of the sound waves that are produced are reflected back after striking a surface. Sound waves can smoothly bounce off the hard objects in the same manner as a rubber ball bounces back the ground.

When a sound wave strikes a hard surface, the sound waves gets reflected back and bounces back to the observer and produces an echo. If the sound waves strikes a soft surface it absorbs the sound.

Although the direction of a sound changes but the echo sounds in the same way as the original sound.

7 0

3 years ago