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STALIN [3.7K]
3 years ago
11

Why do we need to put Airplane mode?

Physics
2 answers:
Serga [27]3 years ago
6 0

Answer:

if we ever ride a airplane we dont mess up its signals and crash ,and its easier to ignore calls and texts

Explanation:

garri49 [273]3 years ago
5 0

Assuming you mean why we need to use airplane mode when flying...

Airplane mode stops all pathways of connection coming and going from your device. It is used on planes so that the pilots can have a clear and direct connection to the ATC Tower, where workers can see the planes radar.

<em>Hope this helps :)</em>

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A cinder cone is formed from relatively ________ viscosity magma with a ________ gas content. low; high high; high low; low high
kenny6666 [7]

<span>A cinder cone is formed from relatively low viscosity magma with a high gas content. Cinder cones are formed by the volcanic ash, cinders that are formed around the volcanic vent. Cinder cones have a bowl shaped crater and the shape of the cinder cones depend on the ejected particles that formed the cinder.</span>

5 0
3 years ago
If a person is 6.25 m away from a 60.0 w speaker, what is the sound level they are hearing?
vodka [1.7K]

Answer:

110.87 dB

Explanation:

(I got it right on Acellus)

I= P/4(pi)r^2 = 60/4(pi)6.25^2

60/4(pi)6.25^2=0.12223

B=10log(I/Io)

B=10log(0.12223/1*10^-12) = 110.87 dB

111 in sigfigs

4 0
3 years ago
Read 2 more answers
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vazorg [7]

As per angular momentum conservation we can say

L_i = L_f

here we know that

mv_1r_1 = mv_2r_2

we know that

v_1 = 1.1 m/s

r_1 = 0.6 m

v_2 = ?

r_2 = 0.15 m

now from above equation

2(1.1)(0.6) = 2(v_2)(0.15)

v_2 = \frac{(1.1)(0.6)}{0.15}

v_2 = 4.4 m/s

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8 0
3 years ago
What is the length x of the side of the triangle below
Shalnov [3]

Answer:

you didn't post any triangles. Thus, the question could not be answered.

8 0
3 years ago
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At the Equator near Earth’s surface, the magnetic field is approximately 82.2 µT northward and the electric field is about 143 N
IrinaK [193]

Answer:

Magnitude of gravitational force of the electron= 3.74×10^12N

Explanation:

Felectron= Fgravitational

Therefore:

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= kq^2/Gm^2

Where G= gravitational constant

m = mass of electron=9.1×10^-31

K= 8.9x10^9

q= 1.6×10^-19

Magnitude of gravitational force= (8.9×10^9)×(1.6×10^-19)^2/(6.7×10^-11)×(9.1×10^-31)

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= 3.74×10^12N

7 0
3 years ago
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