Question

A 2?-ft wide circular track for a camera dolly is set up for a movie scene. The two rails of the track form concentric circles. The radius of the inner circle is 57 ft. How much farther does a wheel on the outer rail travel than a wheel on the inner rail of the track in one? turn?

Answer 1

Answer: A wheel on the outer rail travel 12.57 ft more than a wheel on the inner rail of the track.

Step-by-step explanation:

Since we have given that

Radius of inner circle = 57 ft

As we know the formula for "Circumference of circle":

$Distance=Circumference=2\pi r\\\\Distance=2\times \frac{22}{7}\times 57\\\\Distance=358.28\ Ft$

Since we have also mentioned that there is 2 feet wide circular track for a camera dolly.

So, Radius of outer circle will be given as

$57+2\\=59\ ft$

So, Distance = Circumference is given by

$Distance=2\pi R\\\\Distance=2\times \frac{22}{7}\times 59\\\\Distance=370.85\ ft$

Hence, Difference between the outer rail travel than a wheel on the inner rail travel is given by

$370.85-358.28\\\\=12.57\ ft$

Therefore, A wheel on the outer rail travel 12.57 ft more than a wheel on the inner rail of the track.