2.39x+2.79y=1344.50 where x is regular and y is premium
x+y=550
U will get x=475 y=75
75 gallon premium
Do you want to know what that would be in point slope form? Or what?
Answer:
what you want me to asnwer
you ?????
Step-by-step explanation:
Answer:
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Step-by-step explanation:
Calculation for the equation that can be
use to find the maximum and minimum times for the track team
Using this equation to find the maximum times for the track team
T maximum=T average -7.8 seconds
T maximum=64.6 seconds-7.8 seconds
Using this equation to find the minimum times for the the track team
T minimum=T average +7.8 seconds
T minimum=64.6 seconds +7.8 seconds
Therefore the equation for the maximum and minimum times for the track team are :
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Answer:
Cost to construct the road = 775000 rupees
Step-by-step explanation:
Square field has a side = 150 m
Area of the field = (Side)²
= (150)²
= 22500 m²
Length of the park with road around the field = 150 + 2×(width of the road)
= 150 + (2×5)
= 160 m
Similarly, width of the park with road around the field = 160 m
Area of the park with road = (Side)²
= (160)²
= 25600 m²
Area of road = Area of the park with road - Area of the park
= 25600 - 22500
= 3100 m²
Since, cost of constructing the road = 250 rupees per square meter
Cost to construct the road with the given area = 250 × 3100
= 775000 rupees