In this case, according to the given information about the oxidation numbers anf the compounds given, it turns out possible to figure out the oxidation number of manganese in both MnI2, manganese (II) iodide and MnO2, manganese (IV) oxide, by using the concept of charge balance.
Thus, we can define the oxidation state of iodine and oxygen as -1 and -2, respectively, since the former needs one electron to complete the octet and the latter, two of them.
Next, we can write the following 
, since manganese has five oxidation states, and it is necessary to calculate the appropriate ones:
Next, we multiply each anion's oxidation number by the subscript, to obtain the following:
Thus, the correct choice is Manganese has an oxidation number of +2 in Mnl2 and +4 in MnO2.
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Answer:
was the concentration of the original solution.
Explanation:
(Dilution)
where,
are molarity and volume of non diluted sample.
are molarity and volume of diluted sample.
(1μL=0.001 mL)
Substituting all values :
was the concentration of the original solution.
1identify the #
2place a decimal in a location which would make a #between 1and9
3 count the # of space values that the decimal moved
4 plug the numbers into this formula number from step 2×10 place value
example:
1) 330,000
2) 3.3 0000
3) count the places moved 5
4)plug the # in 3.30×10 to the 5th power.
Answer:Uranium
80 years
To make that nuclear reaction that makes that heat, those uranium pellets are the fuel. And just like any fuel, it gets used up eventually. Your 12-foot-long fuel rod full of those uranium pellet, lasts about six years in a reactor, until the fission process uses that uranium fuel up.
Transuranic wastes, sometimes called TRU, account for most of the radioactive hazard remaining in high-level waste after 1,000 years. Radioactive isotopes eventually decay, or disintegrate, to harmless materials. Some isotopes decay in hours or even minutes, but others decay very slowly.
Explanation:
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